PHP上传多个文件只上传1个文件

时间:2013-07-04 05:02:11

标签: php upload

我编辑了这段代码很多次(im noob whit php)我的问题是使用此代码上传多个文件。我只能上传1个文件。

以下是代码:

<?php
/**
 * uploadFile()
 * 
 * @param string $file_field name of file upload field in html form
 * @param bool $check_image check if uploaded file is a valid image
 * @param bool $random_name generate random filename for uploaded file
 * @return array
 */
function uploadFile ($file_field = null, $check_image = false, $random_name = false) {

  //Config Section    
  //Set file upload path
  $path = 'c:/xampp/htdocs/'; //with trailing slash
  //Set max file size in bytes
  $max_size = 1000000;
  //Set default file extension whitelist
  $whitelist_ext = array('jpg','png','gif');
  //Set default file type whitelist
  $whitelist_type = array('image/jpeg', 'image/png','image/gif');

  //The Validation
  // Create an array to hold any output
  $out = array('error'=>null);

  if (!$file_field) {
    $out['error'][] = "Please specify a valid form field name";           
  }

  if (!$path) {
    $out['error'][] = "Please specify a valid upload path";               
  }

  if (count($out['error'])>0) {
    return $out;
  }

  //Make sure that there is a file
  if((!empty($_FILES[$file_field])) && ($_FILES[$file_field]['error'] == 0)) {

    // Get filename
    $file_info = pathinfo($_FILES[$file_field]['name']);
    $name = $file_info['filename'];
    $ext = $file_info['extension'];

    //Check file has the right extension           
    if (!in_array($ext, $whitelist_ext)) {
      $out['error'][] = "Invalid file Extension";
    }

    //Check that the file is of the right type
    if (!in_array($_FILES[$file_field]["type"], $whitelist_type)) {
      $out['error'][] = "Invalid file Type";
    }

    //Check that the file is not too big
    if ($_FILES[$file_field]["size"] > $max_size) {
      $out['error'][] = "File is too big";
    }

    //If $check image is set as true
    if ($check_image) {
      if (!getimagesize($_FILES[$file_field]['tmp_name'])) {
        $out['error'][] = "Uploaded file is not a valid image";
      }
    }

    //Create full filename including path
    if ($random_name) {
      // Generate random filename
      $tmp = str_replace(array('.',' '), array('',''), microtime());

      if (!$tmp || $tmp == '') {
        $out['error'][] = "File must have a name";
      }     
      $newname = $tmp.'.'.$ext;                                
    } else {
        $newname = $name.'.'.$ext;
    }

    //Check if file already exists on server
    if (file_exists($path.$newname)) {
      $out['error'][] = "A file with this name already exists";
    }

    if (count($out['error'])>0) {
      //The file has not correctly validated
      return $out;
    } 

    if (move_uploaded_file($_FILES[$file_field]['tmp_name'], $path.$newname)) {
      //Success
      $out['filepath'] = $path;
      $out['filename'] = $newname;
      return $out;
    } else {
      $out['error'][] = "Server Error!";
    }

  } else {
    $out['error'][] = "No file uploaded";
    return $out;
  }      
}
?>
<?php
if (isset($_POST['submit'])) {
  $file = uploadFile('file', true, true);
  if (is_array($file['error'])) {
    $message = '';
    foreach ($file['error'] as $msg) {
      $message .= '<p>'.$msg.'</p>';    
    }
  } else {
    $message = "File uploaded successfully";
  }
  echo $message;
}
?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
<input name="file" type="file" size="20" multiple="multiple" />
<input name="submit" type="submit" value="Upload files" />
</form>

请帮助我理解......我知道我必须使用 foreach

5 个答案:

答案 0 :(得分:8)

您需要将文件字段声明为file[]

之类的数组
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
<input name="file[]" type="file" size="20" multiple="multiple" />
<input name="submit" type="submit" value="Upload files" />
</form>

然后尝试

答案 1 :(得分:1)

正如其他人所指出的那样,您需要将上传字段名称更改为ie。 files [](包括名称后面的sqaure括号)。这是相关的,因为它告诉PHP它应该将字段视为数组。

此外,在代码中,您可以使用foreach()来访问上传的文件,如下所示:

foreach ($_FILES['field_name'] as $file)

(显然,在这种情况下,你的html字段将是名称field_name []) 这将在其五次迭代中的每一次中返回一个数组,为您提供有关您已发送的所有文件的信息。例如,如果您发送了两个文件,它可能如下所示:

    ["name"]=>
    array(2) {
      [0]=>
      string(5) "dir.c"
      [1]=>
      string(10) "errcodes.h"
    }
    ["type"]=>
    array(2) {
      [0]=>
      string(11) "text/x-csrc"
      [1]=>
      string(11) "text/x-chdr"
    }
    ["tmp_name"]=>
    array(2) {
      [0]=>
      string(14) "/tmp/phpP1iz5A"
      [1]=>
      string(14) "/tmp/phpf31fzn"
    }
    ["error"]=>
    array(2) {
      [0]=>
      int(0)
      [1]=>
      int(0)
    }
    ["size"]=>
    array(2) {
      [0]=>
      int(511)
      [1]=>
      int(38)
    }
  }

重要的是要理解PHP会将那些不归类为文件,然后给每个文件属性,而是列出所有文件的属性。

我希望现在很清楚。

答案 2 :(得分:0)

您必须使用foreach循环上传多个文件。在框架中你也提供了具有相同设施的组件(即通过使用foreach循环)。

答案 3 :(得分:0)

我的建议是

  1. 开始循环:foreach ($_FILES[$file_field] as $file) {您有// Get filename字符串
  2. 在功能
  3. 的末尾用}关闭它
  4. 将其中的所有$_FILES[$file_field]更改为$file
  5. 当然,输入必须具有multiple属性 Sherin Jose 表示(tut),但现在只有8.27%个浏览器完全支持,所以你最好用JS添加更多输入,比如

    <input type="file" name="file[]" />
    <input type="file" name="file[]" />
    ...
    

    以相同的方式循环它们

答案 4 :(得分:0)

要成功从您的浏览器发送多个文件,您需要输入将数组传递给PHP。这是通过将[]附加到<input>名称的末尾来完成的:

<input type="file" name="filesToUpload[]" multiple>

处理这些文件是棘手的部分。 PHP处理文件上载的方式与处理数组中提供的其他POST或GET数据的方式不同。文件上载在输入的名称和上载的文件的索引之间插入了元数据键。因此$_FILES['filesToUpload']['name'][0]将获取第一个文件的名称,$_FILES['filesToUpload']['name'][1]将获取第二个文件的名称......依此类推。

因为 foreach绝对是错误的循环使用。您最终将自己处理每个元数据,没有任何上下文。 那是非常不自然的

让我们获取每个文件的索引并一次处理一个文件。我们将使用for循环。这是一个完全自包含的功能示例,用户将多个文件上载到服务器上的文件夹中:

<?php
/* 
 * sandbox.php
 */

if (isset($_POST['submit'])) {

    // We need to know how many files the user actually uploaded.
    $numberOfFilesUploaded = count($_FILES['filesToUpload']['name']);

    for ($i = 0; $i < $numberOfFilesUploaded; $i++) {
        // Each iteration of this loop contains a single file.
        $fileName = $_FILES['filesToUpload']['name'][$i];
        $fileTmpName = $_FILES['filesToUpload']['tmp_name'][$i];
        $fileSize = $_FILES['filesToUpload']['size'][$i];
        $fileError = $_FILES['filesToUpload']['error'][$i];
        $fileType = $_FILES['filesToUpload']['type'][$i];

        // PHP has saved the uploaded file as a temporary file which PHP will 
        // delete after the script has ended.
        // Let's move the file to an output directory so PHP will not delete it.
        move_uploaded_file($fileTmpName, './output/' . $fileName);
    }
}

?>

<form method="post" enctype="multipart/form-data">
                              <!-- adding [] Allows us to upload multiple files -->
    <input type="file" name="filesToUpload[]" multiple>
    <input type="submit" name="submit"/>Submit
</form>

要运行此示例,您的文件应如下所示

enter image description here

您可以使用以下命令启动PHP内置Web服务器:

$ php -S localhost:8000

然后转到http://localhost:8000/sandbox.php将运行示例。

重要说明:以上示例未进行任何验证。您需要验证所有上传的文件是否安全。