即时为网站制作应用。它有一个JSON API。我尝试从中获取结果的网址是:http://api.bayfiles.net/v1/account/login/<user>/<password>
我收到错误:使用logcat记录错误时,java.lang.string无法转换为jsonarray。
我的主要活动是:
public class MainActivity extends SherlockActivity {
EditText un,pw;
TextView error;
Button ok;
private ProgressDialog mDialog;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
un = (EditText)findViewById(R.id.user);
pw = (EditText)findViewById(R.id.psw);
ok = (Button)findViewById(R.id.button1);
error = (TextView)findViewById(R.id.textView1);
ok.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
//error.setText("Clicked");
//Intent startNewActivityOpen = new Intent(LoginActivity.this, FilesActivity.class);
//startActivityForResult(startNewActivityOpen, 0);
JsonAsync asyncTask = new JsonAsync();
// Using an anonymous interface to listen for objects when task
// completes.
asyncTask.setJsonListener(new JsonListener() {
public void onObjectReturn(JSONObject object) {
handleJsonObject(object);
}
});
// Show progress loader while accessing network, and start async task.
//mDialog = ProgressDialog.show(this, getSupportActionBar().getTitle(),
// getString(R.string.loading), true);
asyncTask.execute("http://api.bayfiles.net/v1/account/login/spxc/mess2005");
}
});
}
private void handleJsonObject(JSONObject object) {
ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();
try {
JSONArray shows = object.getJSONArray("error");
for (int i = 0; i < shows.length(); i++) {
HashMap<String, String> map = new HashMap<String, String>();
JSONObject e = shows.getJSONObject(i);
//map.put("video_id", String.valueOf(i));
map.put("session", "" + e.getString("session"));
mylist.add(map);
}
} catch (JSONException e) {
Log.e("log_tag", "Error parsing data: " + e.toString());
}
error.setText("session");
/*
//Intent myIntent = new Intent(ListMoviesController.this,
// TestVideoController.class);
myIntent.putExtra("video_title", o.get("video_title"));
myIntent.putExtra("video_channel", o.get("video_channel"));
myIntent.putExtra("video_location", o.get("video_location"));
startActivity(myIntent); */
}{
if (mDialog != null && mDialog.isShowing()) {
mDialog.dismiss();
}
}
}
这是我的适配器:JSONfunctions.java
public class JSONfunctions {
public static JSONObject getJSONfromURL(String url){
InputStream is = null;
String result = "";
JSONObject jArray = null;
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
try {
// Add your data
/*List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("key", "stianxxs"));
nameValuePairs.add(new BasicNameValuePair("secret", "mhfgpammv9f94ddayh8GSweji"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); */
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
//HttpResponse response = httpclient.execute(httppost);
HttpEntity httpEntity = response.getEntity();
is = httpEntity.getContent();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
}catch(Exception e){
Log.e("log_tag", "Error in http connection "+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
try{
jArray = new JSONObject(result);
}catch(JSONException e){
Log.e("log_tag", "Error parsing data "+e.toString());
}
return jArray;
}
}
为什么我收到此错误?在网址中使用正确的用户名和密码时,您将获得:{"error":"","session":"RANDOM NUMBER"}
正如你所看到我试图获取这个数字。任何帮助深表感谢!
答案 0 :(得分:1)
您收到此错误,因为在行
JSONArray shows = object.getJSONArray("error");
您正在尝试获取键error
的值,并将其视为数组,而不是 - 它是一个空字符串。因此,您需要将其作为字符串:
String error = object.getString("error");
同样,如果您需要获得“会话”,可以使用
获取String session = object.getString("session");
P.S。请注意,这假设您的JSONObject object
实际上包含您问题中字符串所代表的对象。