SoapException
应该根据需要格式化响应,而不仅仅是异常消息。任何帮助都感激不尽。
我正在尝试返回一个看起来像这样的SoapException
(例子):
HTTP/1.1 500 Internal Server Error.
Date: Wed, 26 May 2004 05:12:08 GMT
Server: Microsoft-IIS/6.0
X-Powered-By: ASP.NET
X-AspNet-Version: 1.1.4322
Cache-Control: private
Content-Type: text/xml; charset=utf-8
Content-Length: 488
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<soap:Fault>
<faultcode>soap:Server</faultcode>
<faultstring>BlahBlahBlahBlahBlah</faultstring>
<detail />
</soap:Fault>
</soap:Body>
</soap:Envelope>
为此,我实现了这样的代码,取自SoapException
的MSDN网站:
Imports System
Imports System.Web.Services
Imports System.Web.Services.Protocols
Imports System.ComponentModel
Imports System.Xml.Serialization
Imports System.Xml
<System.Web.Services.WebService(Namespace:="http://tempuri.org/")> _
<System.Web.Services.WebServiceBinding(ConformsTo:=WsiProfiles.BasicProfile1_1)> _
<ToolboxItem(False)> _
Public Class Service1
Inherits System.Web.Services.WebService
<WebMethod()>
Public Sub Process()
' Build the detail element of the SOAP fault.
Dim doc As New System.Xml.XmlDocument()
Dim node As System.Xml.XmlNode = doc.CreateNode(XmlNodeType.Element, _
SoapException.DetailElementName.Name, _
SoapException.DetailElementName.Namespace)
' Build specific details for the SoapException.
' Add first child of detail XML element.
Dim details As System.Xml.XmlNode = doc.CreateNode(XmlNodeType.Element, _
"mySpecialInfo1", "http://tempuri.org/")
' Add second child of detail XML element with an attribute.
Dim details2 As System.Xml.XmlNode = doc.CreateNode(XmlNodeType.Element, _
"mySpecialInfo2", "http://tempuri.org/")
Dim attr As XmlAttribute = doc.CreateAttribute("t", "attrName", _
"http://tempuri.org/")
attr.Value = "attrValue"
details2.Attributes.Append(attr)
' Append the two child elements to the detail node.
node.AppendChild(details)
node.AppendChild(details2)
'Throw the exception
Dim se As New SoapException("Fault occurred", SoapException.ClientFaultCode, _
Context.Request.Url.AbsoluteUri, node)
Throw se
Return
End Sub
End Class
然而,当我运行它时,发送的实际响应是:
HTTP/1.1 500 Internal Server Error
Server: ASP.NET Development Server/10.0.0.0
Date: Wed, 03 Jul 2013 13:06:26 GMT
X-AspNet-Version: 2.0.50727
Cache-Control: private
Content-Type: text/plain; charset=utf-8
Content-Length: 233
Connection: Close
System.Web.Services.Protocols.SoapException: Fault occurred
at MyService.Service1.Process() in C:\MyLocation\MyService\Service1.asmx.vb:line 42
如何将响应格式化为:
<soap:Envelope>
<soap:Body>
<soap:Fault>
<faultcode/>
<faultstring/>
<detail/>
</soap:Fault>
</soap:Body>
</soap:Envelope>
答案 0 :(得分:2)
您的代码应该工作,并根据MSDN示例为您提供格式化的错误,或者,如果您想要在发布的响应示例中得到结果,那么这样的服务应该可以解决问题:
Imports System
Imports System.Web.Services
Imports System.Web.Services.Protocols
Imports System.ComponentModel
Imports System.Xml.Serialization
Imports System.Xml
<WebService(Namespace:="http://tempuri.org/")> _
<WebServiceBinding(ConformsTo:=WsiProfiles.BasicProfile1_1)> _
<ToolboxItem(False)> _
Public Class Service1
Inherits WebService
<WebMethod()>
Public Sub Process()
Dim detailsNode As XmlNode = Nothing
Dim actorString As String = Nothing
Throw New SoapException("BlahBlahBlahBlahBlah", SoapException.ServerFaultCode, actorString, detailsNode)
End Sub
End Class
这样的电话:
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:tem="http://tempuri.org/">
<soapenv:Header/>
<soapenv:Body>
<tem:Process/>
</soapenv:Body>
</soapenv:Envelope>
应该返回:
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<soap:Fault>
<faultcode>soap:Server</faultcode>
<faultstring>BlahBlahBlahBlahBlah</faultstring>
<detail/>
</soap:Fault>
</soap:Body>
</soap:Envelope>
您还需要将其添加到Web.config
文件中,以删除故障字符串中的任何堆栈跟踪:
<configuration>
<system.web>
<customErrors mode="On" />
...
...
...
此外,通常不需要手动构建SoapException,但抛出更合适的异常并让ASP.NET将其包装在SoapFault中。有关详细信息,请参阅此处:Using SOAP faults。
使用SoapUI调用您的方法,您应该得到上述结果。确保在SOAP端点上进行POST,例如点击&#34;调用&#34; http://localhost:8080/Service1.asmx
,而不是测试页面的网址例如 http://localhost:8080/Service1.asmx/Process
,因为它不会返回SOAP格式的响应。