Question

我想提取日期与今天相似的记录。

我有这个查询

$query = "select * from calendar_items WHERE expiredate LIKE '$todays_date %' 
    or upcoming_event_featured_date like '$todays_date %' 
    ORDER BY expiredate ASC";

现在我还有3个coming_event_featured_date：coming_event_featured_date2，coming_event_featured_date3，coming_event_featured_date4

所以我想运行一个查询，它将获取的结果的日期与四个coming_event_featured_date的日期相同（coming_event_featured_date，coming_event_featured_date2，coming_event_featured_date3，coming_event_featured_date4）。

查询会是这样的吗？

$query = "select * from calendar_items 
    WHERE expiredate LIKE '$todays_date %' or 
    (upcoming_event_featured_date like '$todays_date %' or 
    upcoming_event_featured_date2 like '$todays_date %' or 
    upcoming_event_featured_date3 like '$todays_date %' or 
    upcoming_event_featured_date4 like '$todays_date %') 
    ORDER BY expiredate ASC";

Answer 1

你一定要听HLGEM并规范化表格结构。但是对于你要求的内容，假设$ todays_date是一个实际日期（如2009-11-16），该查询可能会有效。但是，您可能需要将％移近，以便更安全一点：

$query = "select * from calendar_items 
WHERE expiredate LIKE '{$todays_date}%' or 
(upcoming_event_featured_date like '{$todays_date}%' or 
upcoming_event_featured_date2 like '{$todays_date}%' or 
upcoming_event_featured_date3 like '{$todays_date}%' or 
upcoming_event_featured_date4 like '{$todays_date}%') 
ORDER BY expiredate ASC";

sql查询中的多个条件

1 个答案: