Question

我在PHP变量中编写此代码，其中$ username和$ email被替换。我在屏幕上回应它，它看起来是正确的。我假设MySQL代码存在问题，因为我总是得到的唯一结果是“可接受的”＃。有什么帮助吗？

SELECT CASE 
WHEN email='$email' THEN '$email is already associated with an account' 
WHEN username='$username' THEN '$username is already taken' 
ELSE 'acceptable' 
END AS result FROM collaborator 
UNION 
SELECT CASE 
WHEN email='$email' THEN '$email is already associated with an account' 
WHEN username='$username' THEN '$username is already taken' 
ELSE 'acceptable' 
END AS result 
FROM waitForValidation 
LIMIT 1;

Answer 1

您的问题是在一个或另一个表中无法匹配，因此'acceptable'来自某个地方。然后，您正在使用union，这会删除重复项 - 通常是通过排序。尝试以不同的方式进行比赛：

select (case when max(email) = $email then '$email is already associated with an account' 
             when max(username)='$username' THEN '$username is already taken'
             else 'acceptable'
        end)
from (select email, username
      from collaborator
      where email = '$email' or username= '$username'
      union
      select email, username
      from waitForValidation 
      where email = '$email' or username= '$username'
     ) t

这使用max()代替limit来处理没有匹配的情况。在这种情况下，max()将返回NULL，因此前两个条件将失败。

无法弄清楚为什么每个查询都返回其他（情况何时）

1 个答案: