使用XmlSerializer将对象列表作为c#中的对象列表进行序列化,选择数组项标记

时间:2013-07-02 19:29:46

标签: c# xml serialization

我有这堂课:

[XmlRoot("SIT_ENTRY")]
public class SitEntry
{
    [XmlAttribute("STR_ENTRY_ID", DataType = "string")]
    public string EntryId { get; set; }
}

然后,这一个:

[XmlRoot("SIT_ENTRY_LIST")]
public class SitEntryList : List<SitEntry>
{
}

最后我有了这个功能;

    public string SerializeToString<T>(T value)
    {
        var emptyNamepsaces = new XmlSerializerNamespaces(new[] { XmlQualifiedName.Empty });
        var serializer = new XmlSerializer(value.GetType());
        var settings = new XmlWriterSettings();
        settings.Indent = false;
        settings.OmitXmlDeclaration = true;
        using (var stream = new StringWriter())
        using (var writer = XmlWriter.Create(stream, settings))
        {
            serializer.Serialize(writer, value, emptyNamepsaces);
            return stream.ToString();
        }
    } 

现在,让我们先序列化一下:

var sitentry = new SitEntry
{
    EntryId = "Entry1"
};
var sXml = SerializeToString(sitentry);

xml是<SIT_ENTRY STR_ENTRY_ID="Entry1" />,这正是我想要的。 现在,让我们序列化第二个:

var sitentrylist = new SitEntryList
{
    new SitEntry
    {
        EntryId = "Entry1"
    },
    new SitEntry
    {
        EntryId = "Entry2"
    }
};
sXml = SerializeToString(sitentrylist);

xml是

<SIT_ENTRY_LIST>
    <SitEntry STR_ENTRY_ID="Entry1" />
    <SitEntry STR_ENTRY_ID="Entry2" /> 
</SIT_ENTRY_LIST>

而不是

<SIT_ENTRY_LIST>
    <SIT_ENTRY STR_ENTRY_ID="Entry1" />
    <SIT_ENTRY STR_ENTRY_ID="Entry2" /> 
</SIT_ENTRY_LIST>

正如我所愿。我能怎么做?感谢!!!

2 个答案:

答案 0 :(得分:0)

在旧的XmlSerializer中有关于数组的奇怪行为,我从未弄清楚。我从来没有遇到过类似DataContractSerializer的问题。

您是否有理由不能使用DataContractSerializer? http://msdn.microsoft.com/en-us/library/system.runtime.serialization.datacontractserializer.aspx

[DataContract("SIT_ENTRY")]
public class SitEntry
{
    [DataMember("STR_ENTRY_ID")]
    public string EntryId { get; set; }
}


[DataContract("SIT_ENTRY_LIST")]
public class SitEntryList : List<SitEntry>
{
}

using (MemoryStream requestObjectStream = new MemoryStream())
{   
    DataContractSerializer serializer = new DataContractSerializer(typeof(SitEntry));
    serializer.WriteObject(requestObjectStream, objectToSerialize);
}

答案 1 :(得分:0)

我发现,这是一个可能的解决方案:

[XmlRoot("SIT_ENTRY_LIST")]
public class SitEntryList
{
    [XmlElement("SIT_ENTRY", IsNullable = true)]
    public List<SitEntry> EntryList { get; set; }
}

[...]

var sitentrylist = new SitEntryList
{
    EntryList = new List<SitEntry>
    {
        new SitEntry
        {
            EntryId = "Entry1"
        },
        new SitEntry
        {
            EntryId = "Entry2"
        }
    }
};
s = SerializeToString(sitentrylist);

输出

<SIT_ENTRY_LIST>
    <SIT_ENTRY STR_ENTRY_ID="Entry1" />
    <SIT_ENTRY STR_ENTRY_ID="Entry2" /> 
</SIT_ENTRY_LIST>

我想要的!