Question

我有一点问题，VS给了我2个关于两个值（int []和string []）的警告，这些值是null，因为它们从未被分配，但我确定我分配了它们，这是代码的一部分这与我的问题有关：

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
using ComponentFactory.Krypton.Toolkit;
using System.IO;
namespace DA_Story_Editor
{
public partial class Form1 : ComponentFactory.Krypton.Toolkit.KryptonForm
{
    public Form1()
    {
        InitializeComponent();
    }
    int[] pntrs;
    string[] Strs;

    private void ReadFile(string path1)
    {

        FileStream stream = new FileStream(path1, FileMode.Open, FileAccess.Read);

        for (int i = 0; i < Pntrnum; i++)
        {
            stream.Position = Pntrstrt;
            stream.Read(data, 0, data.Length);
            pntrs[i] = BitConverter.ToInt32(data, 0);
        }
        for (int i = 0; i < Pntrnum; i++)
        {
            byte[] sttrings = new byte[pntrs[i + 1] - pntrs[i]];
            stream.Position = pntrs[i];
            stream.Read(sttrings, 0, sttrings.Length);
            Strs[i] = Encoding.GetEncoding("SHIFT-JIS").GetString(sttrings);

            ListViewItem item = new ListViewItem(new string[]
                {
                    pntrs[i].ToString("X"),
                    Strs[i],
                    Strs[i],
                });
            listView1.Items.AddRange(new ListViewItem[] {item});
        }
    }
}
}

我不确定为什么它会给我这些警告，顺便说一下它也给我一个“NullReferenceException”就行：pntrs[i] = BitConverter.ToInt32(data, 0);

Answer 1

您永远不会构建和分配变量本身 - 但您尝试使用该数组：

// Need to add:
pntrs = new int[Pntrnum];

for (int i = 0; i < Pntrnum; i++)
{
    stream.Position = Pntrstrt;
    stream.Read(data, 0, data.Length);
    pntrs[i] = BitConverter.ToInt32(data, 0);
}

// Need to add:
Strs = new string[Pntrnum];

for (int i = 0; i < Pntrnum; i++)
{
    byte[] sttrings = new byte[pntrs[i + 1] - pntrs[i]];
    stream.Position = pntrs[i];
    stream.Read(sttrings, 0, sttrings.Length);
    Strs[i] = Encoding.GetEncoding("SHIFT-JIS").GetString(sttrings);

整数和字符串上的空值，但它们已经分配

1 个答案: