Question

我无法解析我的XML。它只返回“Item” 我的AndroidActivity无法显示，因为它非常大，这就是为什么我只展示了负责解析的部分。

我的XML看起来像这样：

<MyResource>
<Item>First</Item>
<Item>Second</Item>
</MyResource>

我的ActivityClass方法：

public class ShowItems extends Activity{
    ListView lv;
    ListAdapter adapter;
    static final String KEY_RESOURCE = "MyResource"; // parent node 
    static final String KEY_ITEM = "Item";
    ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();
    String[] from={KEY_ITEM };
    int[] to={R.id.mylist_item};
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        // TODO Auto-generated method stub
        super.onCreate(savedInstanceState);
        setContentView(R.layout.showitems);

        lv=(ListView) findViewById(R.id.lv_items);
        parseXML();
        adapter = new SimpleAdapter(this, mylist,R.layout.list_item,from , to); 
        lv.setAdapter(adapter);
    }

private void parseXML() {
    // TODO Auto-generated method stub
    XMLParser parser = new XMLParser();

    final String URL="http://10.0.2.2:8080/MySite/xml";
    String xml = parser.getXmlFromUrl(URL); 
    Document doc = parser.getDomElement(xml); 
    NodeList nl = doc.getElementsByTagName(KEY_RESOURCE); 
    for (int i = 0; i < nl.getLength(); i++) {

        HashMap<String, String> map = new HashMap<String, String>();
        Element e = (Element) nl.item(i); 
        map.put(KEY_ITEM, parser.getValue(e, KEY_ITEM)); 
        mylist.add(map); }
}

我的XML分析器类：

import java.io.IOException;
import java.io.StringReader;
import java.io.UnsupportedEncodingException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
import android.util.Log;
public class XMLParser {
    public String getXmlFromUrl(String url) { 
        String xml = null; 
        try { 
            HttpClient httpClient = new DefaultHttpClient();
            HttpGet httpGet = new HttpGet(url);
            HttpResponse httpResponse = httpClient.execute(httpGet);
            HttpEntity httpEntity = httpResponse.getEntity(); 
            xml = EntityUtils.toString(httpEntity); 
        } catch (UnsupportedEncodingException e) { 
            e.printStackTrace(); 
        } catch (ClientProtocolException e) { 
            e.printStackTrace(); 
        } catch (IOException e) { 
            e.printStackTrace(); 
        } 
        return xml; 
    }

    public Document getDomElement(String xml){ 
        Document doc = null; 
        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); 
        try { 
            DocumentBuilder db = dbf.newDocumentBuilder(); 
            InputSource is = new InputSource(); 
                is.setCharacterStream(new StringReader(xml)); 
                doc = db.parse(is);  
            } catch (ParserConfigurationException e) { 
                Log.e("Error: ", e.getMessage()); 
                return null; 
            } catch (SAXException e) { 
                Log.e("Error: ", e.getMessage()); 
                return null; 
            } catch (IOException e) { 
                Log.e("Error: ", e.getMessage()); 
                return null; 
            } 
                // return DOM 
            return doc; 
    }

    public String getValue(Element item, String str) {       
        NodeList n = item.getElementsByTagName(str);         
        return this.getElementValue(n.item(0)); 
    } 
    public final String getElementValue( Node elem ) { 
             Node child; 
             if( elem != null){ 
                 if (elem.hasChildNodes()){ 
                     for( child = elem.getFirstChild(); child != null; child = child.getNextSibling() ){ 
                         if( child.getNodeType() == Node.TEXT_NODE  ){ 
                             return child.getNodeValue(); 
                         } 
                     } 
                 } 
             } 
             return ""; 
      } 
}

我无法解析我的XML。这里有什么问题？
它仅返回“项目” 我在ActivityClass中需要做什么，特别是在这部分代码中：

String xml = parser.getXmlFromUrl(URL); 
    Document doc = parser.getDomElement(xml); 
    NodeList nl = doc.getElementsByTagName(KEY_RESOURCE); 
    for (int i = 0; i < nl.getLength(); i++) {


        HashMap<String, String> map = new HashMap<String, String>();
        Element e = (Element) nl.item(i); 
        map.put(KEY_ITEM, parser.getValue(e, KEY_ITEM)); 
        mylist.add(map); }

Answer 1

您的getValue()方法获取MyResource元素，您需要获取MyResource下的所有项目并执行getElementValue()。示例代码是：

   public Map getValue(Element item, String str) {
        NodeList n = item.getElementsByTagName(str);
        for (int i = 0; i < n.getLength(); i++) {
            System.out.println(getElementValue(n.item(i)));
        }
        //Here store it in list/map and return list/map instead of String
        return list/MapHere;
    }

如何在Android XML DOM Parsing中解析相同的名称标记

1 个答案: