Question

我正在尝试在phpMyAdmin中执行此代码。但是，我收到了以下错误

＃1054 - “字段列表”中的未知列“年份”

SELECT
  CONCAT('SELECT year2,',
  GROUP_CONCAT(sums),
  ' FROM yourtable GROUP BY year2')
FROM (
SELECT CONCAT('SUM(name=\'', name, '\') AS `', name, '`') sums
FROM yourtable
GROUP BY name
ORDER BY COUNT(*) DESC
) s
INTO @sql;

PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

查看fiddle以了解实施情况。

如何解决这个问题？任何想法如何在PHP中编写脚本？

Answer 1

Year是MYSQL中的一个已知对象，如果你有一个名为'year'的列，请使用反向勾选'''::

SELECT
  CONCAT('SELECT `year`,',
  GROUP_CONCAT(sums),
  ' FROM yourtable GROUP BY `year`')
FROM (
SELECT CONCAT('SUM(name=\'', name, '\') AS `', name, '`') sums
FROM yourtable
GROUP BY name
ORDER BY COUNT(*) DESC
) s
INTO @sql;

PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

通过phpMyAdmin执行它时MySql＃1054错误

1 个答案: