在android listview上使用过滤时出错?

时间:2013-07-02 06:56:08

标签: android android-listview filtering

我正在尝试在android应用程序中添加过滤到我的listview。它没有正常工作,因为在我的搜索框中写了3-4个字母后给了我异常。

07-02 12:14:48.348: E/AndroidRuntime(22028): FATAL EXCEPTION: main
07-02 12:14:48.348: E/AndroidRuntime(22028): java.lang.IndexOutOfBoundsException: Invalid index 1, size is 1
07-02 12:14:48.348: E/AndroidRuntime(22028):    at java.util.ArrayList.throwIndexOutOfBoundsException(ArrayList.java:251)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at java.util.ArrayList.get(ArrayList.java:304)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.widget.ArrayAdapter.getItem(ArrayAdapter.java:337)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at com.sphinx.indianrailways.adapters.CityAdapter.getView(CityAdapter.java:57)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.widget.AbsListView.obtainView(AbsListView.java:2143)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.widget.ListView.makeAndAddView(ListView.java:1831)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.widget.ListView.fillDown(ListView.java:674)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.widget.ListView.fillSpecific(ListView.java:1332)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.widget.ListView.layoutChildren(ListView.java:1630)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.widget.AbsListView.onLayout(AbsListView.java:1994)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.view.View.layout(View.java:14008)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.view.ViewGroup.layout(ViewGroup.java:4373)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.widget.LinearLayout.setChildFrame(LinearLayout.java:1663)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.widget.LinearLayout.layoutVertical(LinearLayout.java:1521)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.widget.LinearLayout.onLayout(LinearLayout.java:1434)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.view.View.layout(View.java:14008)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.view.ViewGroup.layout(ViewGroup.java:4373)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.widget.FrameLayout.onLayout(FrameLayout.java:448)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.view.View.layout(View.java:14008)
07-02 12:14:48.348: E/AndroidRuntime(22028):    at android.view.ViewGroup.layout(ViewGroup.java:4373)

我的过滤代码如下所示:

filterTextWatcher = new TextWatcher() {

            @Override
            public void onTextChanged(CharSequence cs, int start, int before,
                    int count) {
                // When user changed the Text by typing in search box
                adapter.getFilter().filter(cs);
            }

            @Override
            public void beforeTextChanged(CharSequence arg0, int arg1,
                    int arg2, int arg3) {
                // TODO Auto-generated method stub

            }

            @Override
            public void afterTextChanged(Editable arg0) {
                // TODO Auto-generated method stub
            }
        };

        citySearchBox.addTextChangedListener(filterTextWatcher);

我的StationAdapter.java代码是:

    public class CityAdapter extends ArrayAdapter<City> {
    ArrayList<City> cityLists = new ArrayList<City>();
    private Context context;
    public String noInternet = "No network connectivity.Try again later.";
    City city= null;

    public CityAdapter(Context context, int textViewResourceId,
            ArrayList<City> cityLists) {
        super(context, textViewResourceId, cityLists);
        this.context = context;
        this.cityLists = cityLists;
    }

    static class ViewHolder {
        protected TextView cityCode;
        protected TextView cityName;
    }

    @Override
    public int getCount() {
        return cityLists.size();
    }

    @Override
    public View getView(final int position, View convertView, ViewGroup parent) {
        // TODO Auto-generated method stub

        ViewHolder holder = null;
        if (convertView == null) {
            LayoutInflater inflator = ((Activity) context).getLayoutInflater();
            convertView = inflator.inflate(R.layout.single_city_item, null);
            holder = new ViewHolder();

            holder.cityCode = (TextView) convertView
                    .findViewById(R.id.cityCode);
            holder.cityName = (TextView) convertView
                    .findViewById(R.id.cityName);
            convertView.setTag(holder);
        } else {
            holder = (ViewHolder) convertView.getTag();
        }
        city= getItem(position);

        holder.cityCode.setText(city.getCityCode());
        holder.cityName.setText(city.getCityName());
        return convertView;
    }
}

我知道arraylist当时可能有1个元素并且它试图通过list [1]访问它,这将引发nullpointerexception.But我需要在代码中更改以解决此问题。

1 个答案:

答案 0 :(得分:4)

在我们讨论之后,我认为问题在于:

 @Override
    public int getCount() {
        return cityLists.size();
    }

这使得适配器认为它的大小比正常大(因为它的大小是固定的并且在过滤后没有改变)并且在getView()city= getItem(position);时无法获得属于它的范围的项目正在被召唤。

您应该在问题12和此example中实施Filterable界面(getFilter())。这将在每次调用cityLists时更新getFilter()数组,并且其大小将正常返回,并且还将更新适配器(notifyDataSetChanged()

修改

另一种方法是删除getCount()(让超级方法生效)。这将在每次应用过滤器时更新大小,而不是返回已修复的cityLists.size(),并且让适配器认为其大小大于其拥有的数据。基本上,你要么像你一样实现getCount(),另外要在每次过滤时添加getFilter()来改变cityLists大小,或者让系统处理两者(不要实现getFilter()并且getCount()