我的问题是:我如何读取多行上的字符串作为C中文件的一行字符串?我正在尝试做二进制映射,我的1d数组表示为2d数组。所以这是我的“level_1.txt”:
//start of file
WIDTH: 4
HEIGHT: 5
11,12,13,14,
21,22,23,24,
31,32,33,34,
41,42,43,44,
51,52,53,54,
// eof
我希望得到字符串“11,12,13,14,21,22 ....”
这是我的代码:
int ImportMapDataFromFile(char *fileName, Map *self)
{
FILE *pFile;
char* myStr;
pFile = fopen(fileName, "r");
// Check if the file exists:
if(pFile)
{
// scanf width and height
//fscanf(pFile, "%*s %i %*s %i", &self->width, &self->height);
/*
// this doesnt work
fscanf(pFile, "%*s %i %*s %i %s", &self->width, &self->height, &myStr);
*/
//printf("%i %i", self->width, self->height);
// initialise the array
(self->theScreenMap) = (Grid*)malloc(sizeof(Grid) * self->width * self->height);
// scan the whole remaining file
/*
I dont know how to do this. I tried using fscanf and had a look at fgets
but i cant seem to make it work sorry.
*/
// tokenise it
/*
Pretty sure i have to use strtok right?
http://www.cplusplus.com/reference/cstring/strtok/
*/
// close it
fclose(pFile);
printf("%s \n", &myStr);
return TRUE;
}
else
{
fclose(pFile);
return FALSE;
}
}
我想要做的是读取文件,从前2行获取大小并使用这些值创建1d数组。然后,一旦完成,我想读取剩余的字符串并将其分配给数组。例如
theScreenMap[0] = 11; // first element has 1st token
theScreenMap[1] = 12;
theScreenMap[size - 1] = 54; // last element has last token
感谢有人帮助我。但是如果有人有更好的方法(从文件中读取并初始化数组来创建二进制映射),那么请随时告诉我。谢谢! :)
答案 0 :(得分:4)
这只是您想要的基本实现。最终结果将读取与'height'一样多的行,并将它们连接起来。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAXSIZE 1024
#define MAXLINE 256
char mainArray[MAXSIZE];
char line[MAXLINE];
char *strdup(const char *s) {
char *str = malloc(strlen(s) + 1);
if(str) { strcpy(str, s); }
return str;
}
int main(int argc,char* argv[])
{
int width,height;
unsigned int i=0;
unsigned int count=0;
char **grid;
FILE *fp = fopen("multiline.txt","r");
if(!fp) {perror("multiline.txt");return -1;}
/* Read the width and height */
fscanf(fp,"WIDTH: %d\n",&width);
fscanf(fp,"HEIGHT: %d\n",&height);
printf("Width: %d,\tHeight: %d\n\n",width,height);
while(!feof(fp))
{
fgets(line,MAXLINE,fp);
strncat(mainArray,line,strlen(line)-1); /* get rid of newline */
printf("Line:: %s",line);
printf("MainArray:: %s\n\n",mainArray);
}
/* Get the number of elements */
for(i=0;i<strlen(mainArray);i++)
{
if(mainArray[i]==',')
count++;
}
/* Allocate the grid and tokezine */
grid = malloc(sizeof(grid) * count);
grid[0] = strdup(strtok(mainArray,","));
for(i=1;i<count;i++)
{
grid[i] = strdup(strtok(NULL,","));
}
/* Display */
for(i=0;i<count;i++)
{
printf("grid[%2d]:: %s\n",i,grid[i]);
free(grid[i]); /* free the malloc-ed string */
}
free(grid);
fclose(fp);
return 0;
}
样品的输出:
Width: 4, Height: 5
Line:: 11,12,13,14, MainArray:: 11,12,13,14,
Line:: 21,22,23,24, MainArray:: 11,12,13,14,21,22,23,24,
Line:: 31,32,33,34, MainArray:: 11,12,13,14,21,22,23,24,31,32,33,34,
Line:: 41,42,43,44, MainArray::
11,12,13,14,21,22,23,24,31,32,33,34,41,42,43,44,
Line:: 51,52,53,54, MainArray::
11,12,13,14,21,22,23,24,31,32,33,34,41,42,43,44,51,52,53,54,
Line:: 51,52,53,54, MainArray::
11,12,13,14,21,22,23,24,31,32,33,34,41,42,43,44,51,52,53,54,51,52,53,54,
grid [ 0]:: 11
grid [ 1]:: 12
grid [ 2]:: 13
grid [ 3]:: 14
grid [ 4]:: 21
grid [ 5]:: 22
grid [ 6]:: 23
grid [ 7]:: 24
grid [ 8]:: 31
grid [ 9]:: 32
grid [10]:: 33
grid [11]:: 34
grid [12]:: 41
grid [13]:: 42
grid [14]:: 43
grid [15]:: 44
grid [16]:: 51
grid [17]:: 52
grid [18]:: 53
grid [19]:: 54
grid [20]:: 51
grid [21]:: 52
grid [22]:: 53
grid [23]:: 54