Question

我正在尝试创建一个网络表单应用，允许某人填写表单并上传需要的文件。我目前遇到的问题是，如果用户没有提交文件，它将提示“意外错误”提示。表单确实会将数据提交到电子表格中而不会出错。

如果用户没有上传表单，我需要的是应用程序不会提示错误。

// Script-as-app template.
var submissionSSKey = '0Aud1xlxCWoZydGllMDNwTEVhS3RqSlUyZXBwQVZTcXc';

function doGet(e) {
  var app = UiApp.createApplication().setTitle('Loan Registration Processing');
  var panel = app.createFormPanel();
  var grid = app.createGrid(5,2).setId('loanGrid');
  var nameLabel = app.createLabel('Name:');
  var nameTextBox = app.createTextBox().setName('name').setWidth('150px').setName('name').setId('name');

  var depLabel = app.createLabel("Department:");
  var depSelec = app.createListBox().setWidth('130px').setName('department').setId('department');
  depSelec.addItem('Select Option');
  depSelec.addItem('Cashier');
  depSelec.addItem('Text Books');
  depSelec.addItem('Greeter');
  depSelec.addItem('Runner');
  depSelec.addItem('Line Control');
  depSelec.addItem('IDB');

  var messageLabel = app.createLabel('Message:');
  var messageTextBox = app.createTextArea().setWidth('300px').setHeight('150px').setName('message').setId('message');



  var submitButton = app.createSubmitButton('<B>Submit</B>'); 
  //var warning = app.createHTML('<B>PLEASE WAIT WHILE DATA IS UPLOADING<B>').setStyleAttribute('background','yellow').setVisible(false)

  //file upload
  var upLoadTypeLabel = app.createLabel('Upload Schedule:');
  var upLoad = (app.createFileUpload().setName('thefile'));

  //Grid layout of items on form
  grid.setWidget(0, 0, nameLabel)
  .setWidget(0, 1, nameTextBox)
  .setWidget(1, 0, depLabel)
  .setWidget(1, 1, depSelec)
  .setWidget(2, 0, messageLabel)
  .setWidget(2, 1, messageTextBox)
  .setWidget(3, 0, upLoadTypeLabel)
  .setWidget(3, 1, upLoad)
  .setWidget(4, 0, submitButton)
  //.setWidget(4, 1, warning)

  var cliHandler = app.createClientHandler();
  submitButton.addClickHandler(cliHandler);  
  panel.add(grid);
  app.add(panel);
  return app;

}

 function doPost(e) {
  var app = UiApp.getActiveApplication();
  var comp = 'N/A'
  var LoanType = e.parameter.name;
  var borrower = e.parameter.department;
  var amount = e.parameter.message;
  //app.getElementById('info').setVisible(true).setStyleAttribute('color','red');

  var sheet = SpreadsheetApp.openById(submissionSSKey).getSheets()[0];
  var lastRow = sheet.getLastRow();
  var targetRange = sheet.getRange(lastRow+1, 1, 1, 4).setValues([[comp,LoanType,borrower,amount,]]);
   // data returned is a blob for FileUpload widget


   var fileBlob = e.parameter.thefile;
   var doc = DocsList.getFolderById('0B-d1xlxCWoZybk1oUXhLZV91SDQ').createFile(fileBlob)
                                                              .rename(borrower+' - '+LoanType);




   return app;
 }

Answer 1

首先，我不确定您是否可以使用普通处理程序上传文件。我认为您必须执行POST请求才能上传文件。 See here举个例子。

除此之外，您应该检查文件是否已上传，然后才在驱动器中创建文件。

var fileBlob = e.parameter.thefile;
if (fileBlob != null && fileBlob != undefined && fileBlob != '' ){
   var doc = DocsList.getFolderById('0B-d1xlxCWoZybk1oUXhLZV91SDQ').createFile(fileBlob).rename(borrower+' - '+LoanType);
}

文件上传和表单数据应用脚本出错

1 个答案: