Question

我正在研究通用查询查看器，我还有最后一个需要解决的问题。

假设我有一个返回以下数据的查询...

|  Job Code  | Mon | Tue | Wed | Thu | Fri | Sat | Sun | 
--------------------------------------------------------
|  1234-567  |  0  |  3  |  2  |  5  |  2  |  0  |  0  |
|  3214-431  |  0  |  2  |  4  |  3  |  0  |  0  |  0  |

......等等。当我运行下面的代码时，我在浏览器中得到以下结果。看起来关联数组被填充两次。当我使用MYSQLI_BOTH执行fetch数组时，我已经看到了这一点，但我应该只使用下面的代码获得关联数组。

|  Job Code  | Mon | Tue | Wed | Thu | Fri | Sat | Sun |   Job Code  | Mon | Tue | Wed | Thu | Fri | Sat | Sun | 
--------------------------------------------------------
|  1234-567  |  0  |  3  |  2  |  5  |  2  |  0  |  0  |
|  3214-431  |  0  |  2  |  4  |  3  |  0  |  0  |  0  |

...代码

function query2table( $dbcon, $query )
{
    // Connection is already made.
    $queryResult = mysqli_query($dbcon, $query);
    if( $queryResult )
    {
        echo "<TABLE cellpadding='5' cellspacing='1' border='1'><THEAD><TR>\n";
        while ($hdrrow = mysqli_fetch_assoc($queryResult) )
        {
            foreach ($hdrrow as $hdr => $value) {
                echo "<th>";
                echo $hdr;
                echo "</th>";
            }
        }
        echo "</TR></THEAD>\n";
        mysqli_data_seek($queryResult, 0);
        while ($row = mysqli_fetch_assoc($queryResult,MYSQLI_NUM))
        {
            foreach( $row as $cell )
            {
                echo "<TD>$cell</TD>";
            }

            echo "    </TR>\n";
        }
        echo "</TABLE>\n";

    } else {
        $error = mysqli_error($dbcon);
        echo "\n<BR><BR>dbi_displayQuery - Error reading database: $error<BR><BR>\n";
    }
}

想法？

Answer 1

您循环遍历所有行并输出标题行的次数与结果相同：

while ($hdrrow = mysqli_fetch_assoc($queryResult) )

对于标题行，您只需要获取一行并使用它：

if ($hdrrow = mysqli_fetch_assoc($queryResult) )

PHP mysqli_fetch_assoc列名值

1 个答案: