让我假设我在PHP中有以下对象:
class param{
public $home; //set by another function
public $user; //set by another function
public function createRequest(){
//in this function I want to create mysql string with $home and $user
$sql = "select * FROM table WHERE home =".$this->home." AND user=".$this->user;
return $sql;
}
问题是,$ home(或$ user)可能是空字符串,在这种情况下,我想要包括所有家庭(或用户),而不仅仅是列,其中home =“”(或user =“”);
你有什么建议怎么做吗?或者这个想法是错的? (我只是初学者用PHP)
答案 0 :(得分:1)
这不是最优雅的,我们应该使用PDO编写的语句......但是为了举例:
class param{
public $home; //set by another function
public $user; //set by another function
public function createRequest(){
//in this function I want to create mysql string with $home and $user
$sql = "select * FROM table";
if(strlen($this->home) || strlen($this->user)) {
$sql .= " WHERE ";
$and = array();
if(strlen($this->home))
$and[] = " home='".$this->home."' ";
if(strlen($this->user))
$and[] = " user='".$this->user."' ";
$sql .= implode(" AND ", $and);
}
return $sql;
}
}
示例测试输出:
$p = new param;
echo $p->createRequest();
echo "<br>";
$p->home = "foo";
echo $p->createRequest();
echo "<br>";
$p->user = "bar";
echo $p->createRequest();
echo "<br>";
$p->home = "";
echo $p->createRequest();
将屈服:
select * FROM table
select * FROM table WHERE home='foo'
select * FROM table WHERE home='foo' AND user='bar'
select * FROM table WHERE user='bar'
答案 1 :(得分:0)
class param{
public $home; //set by another function
public $user; //set by another function
public function createRequest(){
//in this function I want to create mysql string with $home and $user
$ClauseArray = array(' 1 = 1 ');
if ($this->home != '') $ClauseArray[] = " home = '".$this->home."' ";
if ($this->user != '') $ClauseArray[] = " user = '".$this->user."' ";
$sql = "select * FROM table WHERE ".implode('AND', $ClauseArray);
return $sql;
}