我希望我的程序能够判断我的两个JTextFields中的内容是整数还是字符串。
CODE
public void actionPerformed(ActionEvent e){
if(inputH.getText().equals(" Set Height ") ||
inputW.getText().equals(" Set Width ")){
JOptionPane.showMessageDialog(frame,
"Change Height And Width To A Number.",
"Change Height To A Number",
JOptionPane.ERROR_MESSAGE);
}
}
});
此if语句测试JTextField中的内容是" Set Height "
还是" Set Width "
,但我希望他们测试其中的内容是否为数字,我该怎么做?
我无法弄清楚Integer.ParseInt
。请帮忙。
答案 0 :(得分:3)
不确定代码中测试的确切位置,但您可以使用此方法确定String是否为整数:
public static boolean isInteger(String s) {
try {
Integer.parseInt(s);
} catch(NumberFormatException e) {
return false;
}
// if exception isn't thrown, then it is an integer
return true;
}
基于这种方式,不需要基于异常的方法,假设您的代码不需要抛出异常:
public static boolean isInt(String s){
for(int i = 0; i < s.length(); i++){
if(!Character.isDigit(s.charAt(i))){
return false;
}
}
return true;
}
答案 1 :(得分:2)
要限制用户输入digits
以外的任何内容,您可以在JTextField
上设置DocumentFilter。
这是一个小例子:
import java.awt.*;
import javax.swing.*;
import javax.swing.text.AbstractDocument;
import javax.swing.text.AttributeSet;
import javax.swing.text.BadLocationException;
import javax.swing.text.DocumentFilter;
import javax.swing.text.DocumentFilter.FilterBypass;
public class InputInteger
{
private JTextField tField;
private MyDocumentFilter documentFilter;
private void displayGUI()
{
JFrame frame = new JFrame("Input Integer Example");
frame.setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE);
JPanel contentPane = new JPanel();
contentPane.setBorder(
BorderFactory.createEmptyBorder(5, 5, 5, 5));
tField = new JTextField(10);
((AbstractDocument)tField.getDocument()).setDocumentFilter(
new MyDocumentFilter());
contentPane.add(tField);
frame.setContentPane(contentPane);
frame.pack();
frame.setLocationByPlatform(true);
frame.setVisible(true);
}
public static void main(String[] args)
{
Runnable runnable = new Runnable()
{
@Override
public void run()
{
new InputInteger().displayGUI();
}
};
EventQueue.invokeLater(runnable);
}
}
class MyDocumentFilter extends DocumentFilter
{
@Override
public void insertString(DocumentFilter.FilterBypass fp
, int offset, String string, AttributeSet aset)
throws BadLocationException
{
int len = string.length();
boolean isValidInteger = true;
for (int i = 0; i < len; i++)
{
if (!Character.isDigit(string.charAt(i)))
{
isValidInteger = false;
break;
}
}
if (isValidInteger)
super.insertString(fp, offset, string, aset);
else
Toolkit.getDefaultToolkit().beep();
}
@Override
public void replace(DocumentFilter.FilterBypass fp, int offset
, int length, String string, AttributeSet aset)
throws BadLocationException
{
int len = string.length();
boolean isValidInteger = true;
for (int i = 0; i < len; i++)
{
if (!Character.isDigit(string.charAt(i)))
{
isValidInteger = false;
break;
}
}
if (isValidInteger)
super.replace(fp, offset, length, string, aset);
else
Toolkit.getDefaultToolkit().beep();
}
}
@Override
public void insertString(FilterBypass fb, int off
, String str, AttributeSet attr)
throws BadLocationException
{
// remove non-digits
fb.insertString(off, str.replaceAll("\\D++", ""), attr);
}
@Override
public void replace(FilterBypass fb, int off
, int len, String str, AttributeSet attr)
throws BadLocationException
{
// remove non-digits
fb.replace(off, len, str.replaceAll("\\D++", ""), attr);
}
答案 2 :(得分:-1)
您也可以使用action
方法处理关键事件。试试这个
首先制作JTextField
JTextField j=new JTextField();
然后将KeyListner
添加到此JTextField
j.addKeyListener(new KeyListener() {
@Override
public void keyTyped(KeyEvent arg0) {
// TODO Auto-generated method stub
}
@Override
public void keyReleased(KeyEvent arg0) {
// TODO Auto-generated method stub
if(arg0.getKeyCode()>57 || arg0.getKeyCode()<48) {
//your error message and other handling code here
JOptionPane.showMessageDialog(PatentFrame, "Only integer allowed", "Message title",JOptionPane.ERROR_MESSAGE);
}
}
@Override
public void keyPressed(KeyEvent arg0) {
// TODO Auto-generated method stub
}
});
48是0的ASCII码,57是9的ASCII码。你也可以忽略像shift这样的虚拟键。 See ASCII chart