我正在使用D3.js绘制像example中的可折叠树形图。它工作得很好,但是当图表进入正常功能时,图表的大小可能会发生巨大变化(即我现在拥有的几个节点,而不是我的批次更多)。
我想让SVG区域滚动,我已经尝试了我在网上找到的所有东西,但它没有成功。我工作的最好的是使用d3.behaviour.drag
,我在其中拖动整个图表。它远非最佳和毛刺,但它有点可用。
即便如此,我还是试着清理一下,我意识到d3.behaviour.zoom
也可以用来 pan SVG区域,根据API文档。< / p>
问题:任何人都可以解释如何使其适应我的代码吗?
我希望能够用图表 pan SVG区域,如果可能的话,它会对一些误用做出反应,即尝试将图表平移出视口,并启用缩放到最大视口的尺寸...
到目前为止,这是我的代码:
var realWidth = window.innerWidth;
var realHeight = window.innerHeight;
function load(){
callD3();
}
var m = [40, 240, 40, 240],
w = realWidth -m[0] -m[0],
h = realHeight -m[0] -m[2],
i = 0,
root;
var tree = d3.layout.tree()
.size([h, w]);
var diagonal = d3.svg.diagonal()
.projection(function(d) { return [d.y, d.x]; });
var vis = d3.select("#box").append("svg:svg")
.attr("class","svg_container")
.attr("width", w)
.attr("height", h)
.style("overflow", "scroll")
.style("background-color","#EEEEEE")
.append("svg:g")
.attr("class","drawarea")
.attr("transform", "translate(" + m[3] + "," + m[0] + ")")
;
var botao = d3.select("#form #button");
function callD3() {
//d3.json(filename, function(json) {
d3.json("D3_NEWCO_tree.json", function(json) {
root = json;
d3.select("#processName").html(root.text);
root.x0 = h / 2;
root.y0 = 0;
botao.on("click", function(){toggle(root); update(root);});
update(root);
});
function update(source) {
var duration = d3.event && d3.event.altKey ? 5000 : 500;
// Compute the new tree layout.
var nodes = tree.nodes(root).reverse();
// Normalize for fixed-depth.
nodes.forEach(function(d) { d.y = d.depth * 50; });
// Update the nodes…
var node = vis.selectAll("g.node")
.data(nodes, function(d) { return d.id || (d.id = ++i); });
// Enter any new nodes at the parent's previous position.
var nodeEnter = node.enter().append("svg:g")
.attr("class", "node")
.attr("transform", function(d) { return "translate(" + source.y0 + "," + source.x0 + ")"; })
.on("click", function(d) { toggle(d); update(d); });
nodeEnter.append("svg:circle")
.attr("r", function(d){
return Math.sqrt((d.part_cc_p*1))+4;
})
.attr("class", function(d) { return "level"+d.part_level; })
.style("stroke", function(d){
if(d._children){return "blue";}
})
;
nodeEnter.append("svg:text")
.attr("x", function(d) { return d.children || d._children ? -((Math.sqrt((d.part_cc_p*1))+6)+this.getComputedTextLength() ) : Math.sqrt((d.part_cc_p*1))+6; })
.attr("y", function(d) { return d.children || d._children ? -7 : 0; })
.attr("dy", ".35em")
.attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })
.text(function(d) {
if(d.part_level>0){return d.name;}
else
if(d.part_multi>1){return "Part " + d.name+ " ["+d.part_multi+"]";}
else{return "Part " + d.name;}
})
.attr("title",
function(d){
var node_type_desc;
if(d.part_level!=0){node_type_desc = "Labour";}else{node_type_desc = "Component";}
return ("Part Name: "+d.text+"<br/>Part type: "+d.part_type+"<br/>Cost so far: "+d3.round(d.part_cc, 2)+"€<br/>"+"<br/>"+node_type_desc+" cost at this node: "+d3.round(d.part_cost, 2)+"€<br/>"+"Total cost added by this node: "+d3.round(d.part_cost*d.part_multi, 2)+"€<br/>"+"Node multiplicity: "+d.part_multi);
})
.style("fill-opacity", 1e-6);
// Transition nodes to their new position.
var nodeUpdate = node.transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; });
nodeUpdate.select("circle")
.attr("r", function(d){
return Math.sqrt((d.part_cc_p*1))+4;
})
.attr("class", function(d) { return "level"+d.part_level; })
.style("stroke", function(d){
if(d._children){return "blue";}else{return null;}
})
;
nodeUpdate.select("text")
.style("fill-opacity", 1);
// Transition exiting nodes to the parent's new position.
var nodeExit = node.exit().transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
.remove();
nodeExit.select("circle")
.attr("r", function(d){
return Math.sqrt((d.part_cc_p*1))+4;
});
nodeExit.select("text")
.style("fill-opacity", 1e-6);
// Update the links…
var link = vis.selectAll("path.link")
.data(tree.links(nodes), function(d) { return d.target.id; });
// Enter any new links at the parent's previous position.
link.enter().insert("svg:path", "g")
.attr("class", "link")
.attr("d", function(d) {
var o = {x: source.x0, y: source.y0};
return diagonal({source: o, target: o});
})
.transition()
.duration(duration)
.attr("d", diagonal);
// Transition links to their new position.
link.transition()
.duration(duration)
.attr("d", diagonal);
// Transition exiting nodes to the parent's new position.
link.exit().transition()
.duration(duration)
.attr("d", function(d) {
var o = {x: source.x, y: source.y};
return diagonal({source: o, target: o});
})
.remove();
$('svg text').tipsy({
fade:true,
gravity: 'nw',
html:true
});
// Stash the old positions for transition.
nodes.forEach(function(d) {
d.x0 = d.x;
d.y0 = d.y;
});
var drag = d3.behavior.drag()
.origin(function() {
var t = d3.select(this);
return {x: t.attr("x"), y: t.attr("y")};
})
.on("drag", dragmove);
d3.select(".drawarea").call(drag);
}
// Toggle children.
function toggle(d) {
if (d.children) {
d._children = d.children;
d.children = null;
} else {
d.children = d._children;
d._children = null;
}
}
function dragmove(){
d3.transition(d3.select(".drawarea"))
.attr("transform", "translate(" + d3.event.x +"," + d3.event.y + ")");
}
}
答案 0 :(得分:20)
您可以在此处查看(大部分)有效的实施方案:http://jsfiddle.net/nrabinowitz/fF4L4/2/
这里的关键部分:
在d3.behavior.zoom()
元素上调用svg
。这需要svg
元素设置pointer-events: all
。您也可以在子元素上调用它,但是如果您希望整个事物平移和缩放,我没有看到原因,因为您基本上希望整个SVG区域响应平移/缩放事件。
d3.select("svg")
.call(d3.behavior.zoom()
.scaleExtent([0.5, 5])
.on("zoom", zoom));
在此设置scaleExtent
可让您限制缩放比例。您可以将其设置为[1, 1]
以完全禁用缩放,或者以编程方式将其设置为内容的最大大小,如果这是您想要的(我不确定这里到底是什么)。
zoom
函数类似于dragmove
函数,但包含比例因子并设置了平移偏移的限制(据我所知,d3没有任何限制)内置panExtent
支持):
function zoom() {
var scale = d3.event.scale,
translation = d3.event.translate,
tbound = -h * scale,
bbound = h * scale,
lbound = (-w + m[1]) * scale,
rbound = (w - m[3]) * scale;
// limit translation to thresholds
translation = [
Math.max(Math.min(translation[0], rbound), lbound),
Math.max(Math.min(translation[1], bbound), tbound)
];
d3.select(".drawarea")
.attr("transform", "translate(" + translation + ")" +
" scale(" + scale + ")");
}
(老实说,我认为我没有正确的左右阈值逻辑 - 这似乎不会限制放大时的正确拖动。左边作为读者的练习:) 。)
为了简化这里的事情,让g.drawarea
元素没有初始变换是有帮助的 - 所以我在外层包装器中添加了另一个g
元素来设置边距偏移量: / p>
vis // snip
.append("svg:g")
.attr("class","drawarea")
.append("svg:g")
.attr("transform", "translate(" + m[3] + "," + m[0] + ")");
这里的其他更改只是为了让您的代码在JSFiddle中更好地工作。这里有一些缺失的细节,但希望这足以让你开始。