Question

我有一个JSON文件，其中读取对象并在div中显示它们。但我只需要显示五个对象而不是全部。

以下是我正在使用的代码

$.each(recentActdata.slice(0,5), function(i, data) {
            var ul_data = "<li><h3>"+ renderActionLink(data)+ "</h3></li>";
            $("#recentActivities").append(ul_data);
        });

但这片似乎不起作用。我的JSON格式是

[   
{ 
    "displayValue":"Updated Guidelines", 
    "link":"#",
    "timestamp":"29/06/2013 01:32"
},
{ 
    "displayValue":"Logging", 
    "link":"#",
    "timestamp":"28/06/2013 16:19"
},
{ 
    "displayValue":"Subscribe", 
    "link":"#",
    "timestamp":"21/06/2013 14:30"
},
{ 
    "displayValue":"Artifactory Vs Nexus", 
    "link":"#",
    "timestamp":"21/06/2013 13:39"
},
{ 
    "displayValue":"CTT - Java 7", 
    "link":"#",
    "timestamp":"20/06/2013 13:30"
},
{ 
    "displayValue":"Added Artifactory Server", 
    "link":"#",
    "timestamp":"19/06/2013 23:39"
},
{ 
    "displayValue":"Estimation Template", 
    "link":"#",
    "timestamp":"19/06/2013 23:39"
},
{ 
    "displayValue":"GZIP compression in Tomcat", 
    "link":"#",
    "timestamp":"14/06/2013 23:39"
},
{ 
    "displayValue":"HBase Basics", 
    "link":"#",
    "timestamp":"12/06/2013 23:39"
}
 ]

请建议如何实现这一目标。我不能给我的JSON起名字。

Answer 1

您发布的代码运作正常！

以下是演示：http://jsfiddle.net/enXcn/1/

请注意，当您更改切片的值时，会显示更多或更少的元素，这是您应该执行的操作。

HTML: <div id="recentActivities"></div>

JS：

var recentActdata = [   
{ 
    "displayValue":"Updated Guidelines", 
    "link":"#",
    "timestamp":"29/06/2013 01:32"
},
{ 
    "displayValue":"Logging", 
    "link":"#",
    "timestamp":"28/06/2013 16:19"
},
{ 
    "displayValue":"Subscribe", 
    "link":"#",
    "timestamp":"21/06/2013 14:30"
},
{ 
    "displayValue":"Artifactory Vs Nexus", 
    "link":"#",
    "timestamp":"21/06/2013 13:39"
},
{ 
    "displayValue":"CTT - Java 7", 
    "link":"#",
    "timestamp":"20/06/2013 13:30"
},
{ 
    "displayValue":"Added Artifactory Server", 
    "link":"#",
    "timestamp":"19/06/2013 23:39"
},
{ 
    "displayValue":"Estimation Template", 
    "link":"#",
    "timestamp":"19/06/2013 23:39"
},
{ 
    "displayValue":"GZIP compression in Tomcat", 
    "link":"#",
    "timestamp":"14/06/2013 23:39"
},
{ 
    "displayValue":"HBase Basics", 
    "link":"#",
    "timestamp":"12/06/2013 23:39"
}
 ];


$.each(recentActdata.slice(0,5), function(i, data) {
            var ul_data = "<li><h3>"+ data.displayValue+ "</h3></li>";
            $("#recentActivities").append(ul_data);
        });

切片JSON数组以获取前五个对象

1 个答案: