Question

我正在尝试编写一个以xml格式返回数据的servlet。我正在尝试为该特定请求生成唯一ID，并且当我尝试在XML请求中添加uuid时，我总是在浏览器上收到以下错误 -

   This page contains the following errors:

error on line 2 at column 14: AttValue: " or ' expected
Below is a rendering of the page up to the first error.

这就是我的代码的样子 -

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    final String uuid = UUID.randomUUID().toString().replaceAll("-", "");     
    System.out.println("uuid = " + uuid);

    response.setContentType("application/xml");
    PrintWriter writer = response.getWriter();
    writer.println("<?xml version=\"1.0\"?>");
    writer.println("<request uuid = "+uuid+">");
    writer.println("<app hash = \"abc\"/>");
    writer.println("<app hash = \"def\"/>");
    writer.println("</request>");
    writer.flush();
}

我的上述代码有问题吗？谁能指导我，我做错了什么？

感谢您的帮助!!

Answer 1

我猜你应该把你的UUID放在引号之下：

writer.println("<request uuid = \""+uuid+"\">");

请注意额外的

\“

围绕uuid。

Answer 2

您忘记了属性值周围的"，更改：

 writer.println("<request uuid = "+uuid+">");

到

 writer.println("<request uuid = \""+uuid+"\">");

它应该有用。

将UUID添加到servlet中的XML请求

2 个答案: