Question

这是我的 dad 类

 public class Dad
    {
        public string Name
        {
            get;set;
        }
        public Dad(string name)
        {
            Name = name;
        }
    }

这是我的测试方法

public void TestDad()
        {
           UnityContainer DadContainer= new UnityContainer();
           Dad newdad = DadContainer.Resolve<Dad>();    
           newdad.Name = "chris";    
           Assert.AreEqual(newdad.Name,"chris");                 
        }

这是我得到的错误

"InvalidOperationException - the type String cannot be constructed.
 You must configure the container to supply this value"

如何配置DadContainer以使此断言通过？谢谢

Answer 1

您应该提供无参数构造函数：

public class Dad
{
    public string Name { get; set; }

    public Dad()
    {
    }

    public Dad(string name)
    {
        Name = name;
    }
}

如果您不能提供无参数构造函数，则需要配置容器以提供它，方法是直接将其注册到容器中：

UnityContainer DadContainer = new UnityContainer();
DadContainer.RegisterType<Dad>(
    new InjectionConstructor("chris"));

或通过app / web.config文件：

<configSections>
  <section name="unity" type="Microsoft.Practices.Unity.Configuration.UnityConfigurationSection, Microsoft.Practices.Unity.Configuration"/>
</configSections>

<unity>
  <containers>
    <container>
      <register type="System.String, MyProject">
        <constructor>
          <param name="name" value="chris" />
        </constructor>
      </register >
    </container>
  </containers>
</unity>

如何配置unity容器来提供字符串构造函数值？

1 个答案: