Question

我使用Spring Tool Suite在eclipse中开发一个简单的Spring 3。但是当我运行时，“HTTP状态404请求的资源（/ hxj /）不可用”是返回。

在eclipse的控制台中：没有错误，但有些信息看起来很奇怪：

Jun 29, 2013 7:50:47 PM org.apache.catalina.loader.WebappClassLoader validateJarFile
INFO: validateJarFile(H:\My Documents\eclipse\.metadata\.plugins\org.eclipse.wst.server.core 
\tmp1\wtpwebapps\Spring\WEB-INF\lib\jsp-api-2.1.jar) - jar not loaded. 

Jun 29, 2013 7:50:47 PM org.apache.catalina.loader.WebappClassLoader validateJarFile
INFO: validateJarFile(H:\My Documents\eclipse\.metadata\.plugins\org.eclipse.wst.server.core 
\tmp1\wtpwebapps\Spring\WEB-INF\lib\servlet-api-2.5.jar) - jar not loaded.

以下是我的web.xml：

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>

<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listene-class>
</listener>

<!-- Processes application requests -->
<servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>*.do</url-pattern>
</servlet-mapping>
<welcome-file-list>
    <welcome-file>home.jsp</welcome-file>
</welcome-file-list>
</web-app>

java类的主要部分：HomeController.java

package com.hxj.hxj;


@Controller
public class HomeController {

private static final Logger logger = LoggerFactory.getLogger(HomeController.class);

@RequestMapping(value = "/home", method = RequestMethod.GET)
public String home(Locale locale, Model model) {
    logger.info("Welcome home! The client locale is {}.", locale);

    Date date = new Date();
            DateFormat dateFormat 
               = DateFormat.getDateTimeInstance(DateFormat.LONG,  DateFormat.LONG, locale);

    String formattedDate = dateFormat.format(date);

    model.addAttribute("serverTime", formattedDate );

    return "home";
}

}

servlet-context.xml：

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org
        /schema/mvc/spring-mvc.xsd
     http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans 
    /spring-beans.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema
/context/spring-context.xsd">

<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->

<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />


<resources mapping="/resources/**" location="/resources/" />

<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <beans:property name="prefix" value="/WEB-INF/views/" />
    <beans:property name="suffix" value=".jsp" />
</beans:bean>

<context:component-scan base-package="com.hxj.hxj" />

</beans:beans>

我不知道它为什么不起作用，因为它是一个来自spring templete项目的春季MVC项目。任何人都可以帮我解决这个问题吗？

非常感谢！伊芙

编辑：此外，为什么网址是：localhost：8080 / hxj / 而不是：localhost：8080 / hxj / home.jsp（或/home.do）？

由于

Answer 1

Acdcjunior在评论中非常严格：

在web.xml中尝试制作：

<servlet-mapping> 
     <servlet-name>appServlet</servlet-name>
     <url-pattern>/*</url-pattern>
</servlet-mapping>

而不是* .do。

你问：

此外，为什么url是：localhost：8080 / hxj /而不是：localhost：8080 / hxj / home.jsp（或/home.do）？

我希望正确的网址为：localhost:8080/hxj/home （localhost:8080/hxj/仅适用于web.XML中的欢迎URL映射）

这是因为那是您为控制器方法指定的请求映射。它不是* .jsp，因为在Spring中你使用url来指定应该调用哪个控制器方法，而不是直接指定jsp。（而且它不是* .do因为这不是支柱）

Answer 2

在文件HomeController.java中尝试

package com.hxj.hxj;


@Controller
@RequestMapping(value = "/home", method = RequestMethod.GET)
public class HomeController {

private static final Logger logger = LoggerFactory.getLogger(HomeController.class);

@RequestMapping( method = RequestMethod.GET)
public String home(Locale locale, Model model) {
logger.info("Welcome home! The client locale is {}.", locale);

Date date = new Date();
        DateFormat dateFormat 
           = DateFormat.getDateTimeInstance(DateFormat.LONG,  DateFormat.LONG, locale);

String formattedDate = dateFormat.format(date);

model.addAttribute("serverTime", formattedDate );

return "home";
}
}

你的src \ main \ webapp中的

放了redirect.jsp

<%@page contentType="text/html" pageEncoding="UTF-8"%>
<% response.sendRedirect("home"); %>

在web.xml中添加welcome-file-list

<welcome-file-list>
    <welcome-file>redirect.jsp</welcome-file>
</welcome-file-list>

Servlet映射

<servlet-mapping> 
   <servlet-name>appServlet</servlet-name>
   <url-pattern>/</url-pattern>
</servlet-mapping>

确保/ WEB-INF / views /目录中的文件home.jsp

Spring 3 HTTP状态404

2 个答案: