我尝试在意图上发送字符串时出错

时间:2013-06-29 15:35:39

标签: java android android-intent

我有一个应用程序,其中许多活动打开另一个,其中一些东西设置在打开它的按钮(图像,标签等)后。在此活动关闭后,我想返回一个字符串vith值“1 “将转换为int并用于设置分数。

在返回的活动中我有这个:

Intent i;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        // TODO Auto-generated method stub
        super.onCreate(savedInstanceState);
        setContentView(R.layout.vie);
        img = (ImageView) findViewById(R.id.img);
        et = (EditText) findViewById(R.id.et);
        btn = (Button) findViewById(R.id.btnCheck);
        txt = (TextView) findViewById(R.id.txt);

        win_sound = MediaPlayer.create(Vie.this, R.raw.win);
        wrong_sound= MediaPlayer.create(Vie.this, R.raw.wrong);

        i = getIntent();
        Bitmap back = i.getParcelableExtra("back");
        Drawable b = new BitmapDrawable(getResources(), back);
        img.setImageDrawable(b);
        String tag = i.getStringExtra("tag");
        Object tag2 = (Object) tag;
        img.setTag(tag2);
        btn.setOnClickListener(this);

    }

    @Override
    public void onClick(View arg0) {
        // TODO Auto-generated method stub
        boolean mb = check(et, img);
        if (mb) {
            // Sunet toast thread
            txt.setText(title(img));
            win_sound.start();
            i.putExtra("score", "1");
            setResult(RESULT_OK, i);

            Thread t = new Thread() {

                @Override
                public void run() {
                    // TODO Auto-generated method stub
                    super.run();
                    try {
                        sleep(win_sound.getDuration());

                    } catch (Exception e) {
                        // TODO: handle exception
                        e.printStackTrace();
                    } finally {
                        finish();
                    }

                }

            };

            t.start();

        }

        if (!mb) {
            // sunet toast thread
            wrong_sound.start();
            Toast t = Toast.makeText(getApplicationContext(),"Wrong answer! Please check if you have spelled corectly the name of the team!",Toast.LENGTH_LONG);
            t.show();
        }
    }

OnActivityResult方法:

int a = 0
@Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        // TODO Auto-generated method stub
        super.onActivityResult(requestCode, resultCode, data);
        if (data.getExtras().containsKey("score")) {
            a +=Integer.valueOf(data.getStringExtra("score")); 
        }

    }

并设置textView以显示:

txtScore.setText(a)的

但是这给了我一个错误,这是我的LogCat:

06-29 15:28:25.312: E/AndroidRuntime(981): Caused by: android.content.res.Resources$NotFoundException: String resource ID #0x0
06-29 15:28:25.312: E/AndroidRuntime(981):  at android.content.res.Resources.getText(Resources.java:230)
06-29 15:28:25.312: E/AndroidRuntime(981):  at android.widget.TextView.setText(TextView.java:3769)
06-29 15:28:25.312: E/AndroidRuntime(981):  at com.RandDdev.uclquiz.Teams.onCreate(Teams.java:61)

你能帮帮我吗?

3 个答案:

答案 0 :(得分:2)

txtScore.setText(a); 

a是Integer。所以Android正在寻找带有该ID的R里面的String。

改变
txtScore.setText(String.valueOf(a));

您使用的是setText(int),而不是setText(Charsequence)

答案 1 :(得分:2)

您应该使用以下

   txtScore.setText(String.valueOf(a));

public final void setText (int resid)

http://developer.android.com/reference/android/widget/TextView.html

因此它会查找一个int值的资源ID。这不存在。因此,您将获得资源未找到异常

答案 2 :(得分:0)

请尝试txtScore.setText(“”+ a); 您不能直接将int设置为TextView