Question

我正试图将用户最近的Instagram媒体放在侧边栏上。我正在尝试使用Instagram API来获取媒体。

http://instagram.com/developer/endpoints/users/

文档说明了GET https://api.instagram.com/v1/users/<user-id>/media/recent/，但它说要传递OAuth访问令牌。访问令牌代表代表用户行事的授权。我不希望用户登录Instagram以在侧栏上看到这一点。他们甚至不需要拥有Instagram帐户。

例如，我可以在没有登录Instagram并查看照片的情况下前往http://instagram.com/thebrainscoop。我想通过API来做到这一点。

在Instagram API中，未经用户身份验证的请求会传递client_id而不是access_token。但是，如果我尝试这样做，我会得到：

{
  "meta":{
    "error_type":"OAuthParameterException",
    "code":400,
    "error_message":"\"access_token\" URL parameter missing. This OAuth request requires an \"access_token\" URL parameter."
  }
}

那么，这不可能吗？没有要求用户首先通过OAuth登录Instagram帐户，是否无法获取用户的最新（公共）媒体？

Answer 1

＆＃13;

var name = "smena8m";
$.get("https://images"+~~(Math.random()*33)+"-focus-opensocial.googleusercontent.com/gadgets/proxy?container=none&url=https://www.instagram.com/" + name + "/", function(html) {
    if (html) {
        var regex = /_sharedData = ({.*);<\/script>/m,
          json = JSON.parse(regex.exec(html)[1]),
          edges = json.entry_data.ProfilePage[0].graphql.user.edge_owner_to_timeline_media.edges;
      $.each(edges, function(n, edge) {
          var node = edge.node;
          $('body').append(
              $('<a/>', {
              href: 'https://instagr.am/p/'+node.shortcode,
              target: '_blank'
          }).css({
              backgroundImage: 'url(' + node.thumbnail_src + ')'
          }));
      });
    }
});

＆＃13;

html, body {
  font-size: 0;
  line-height: 0;
}

a {
  display: inline-block;
  width: 25%;
  height: 0;
  padding-bottom: 25%;
  background: #eee 50% 50% no-repeat;
  background-size: cover;
}

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

＆＃13;

您可以使用着陆页地址like this旁边的?__a=1以JSON格式下载任何Instagram用户照片Feed。无需获取用户ID或注册应用程序，无需令牌，也无需oAuth。

min_id和max_id变量可用于分页，此处为example

YQL可能无法在剪切的iframe中使用，因此您始终可以在YQL Console中手动检查

2018年4月更新：在最新的Instagram更新后，您无法在客户端（javascript）执行此操作，因为签名请求的自定义标头无法使用javascript设置CORS {{1限制。仍然可以通过Access-Control-Allow-Headers或任何其他服务器端方法执行此操作，并使用基于php，rhx_gis和请求参数的正确签名。您可以阅读更多相关信息here。

2019年1月更新：YQL已停用，因此，请将我的最新更新与Google Image Proxy一起检查为Instagram页面的csrf_token代理！然后只有负面的时刻 - 这种方法没有分页。

CORS解决方案：

PHP

Answer 2

这已经很晚了，但是如果有人帮助我，我会在Instagram的文档中看不到它。

要在https://api.instagram.com/v1/users/<user-id>/media/recent/上执行GET（目前正在撰写），您实际上不需要OAuth访问令牌。

您可以执行https://api.instagram.com/v1/users/[USER ID]/media/recent/?client_id=[CLIENT ID]

[客户ID]将是通过管理客户在应用程序中注册的有效客户端ID（与用户无关）。您可以通过执行GET用户搜索请求从用户名获取[USER ID]： https://api.instagram.com/v1/users/search?q=[USERNAME]&client_id=[CLIENT ID]

Answer 3

<强>二○一七年十一月十一日
由于Instagram改变了他们提供这些数据的方式，现在上述方法都没有用。以下是获取用户媒体的新方法：
获取https://instagram.com/graphql/query/?query_id=17888483320059182&variables={"id":"1951415043","first":20,"after":null}
其中：
query_id - 永久值： 17888483320059182 （请注意以后可能会更改。）
id - 用户的ID。它可能带有用户列表。要获取用户列表，您可以使用以下请求：GET https://www.instagram.com/web/search/topsearch/?context=blended&query=YOUR_QUERY
first - 要获得的物品数量 after - 如果您想从该ID获取项目，则为最后一项的ID。

Answer 4

截至上周，Instagram已停用/media/网址，我实施了一种解决方法，目前效果非常好。

为了解决这个问题中的每个人的问题，我写了这个：https://github.com/whizzzkid/instagram-reverse-proxy

它使用以下端点提供所有Instagram的公共数据：

获取用户媒体：

https://igapi.ga/<username>/media
e.g.: https://igapi.ga/whizzzkid/media

获取具有限制计数的用户媒体：

https://igapi.ga/<username>/media?count=N // 1 < N < 20
e.g.: https://igapi.ga/whizzzkid/media?count=5

使用JSONP：

https://igapi.ga/<username>/media?callback=foo
e.g.: https://igapi.ga/whizzzkid/media?callback=bar

代理API还会将下一页和上一页网址附加到响应中，因此您无需在最后计算该内容。

希望你们喜欢它！

感谢@ 350D发现这一点：）

Answer 5

Instagram API需要通过OAuth进行用户身份验证才能访问用户的最新媒体端点。现在似乎没有任何其他方式可以为用户获取所有媒体。

Answer 6

如果您正在寻找一种生成访问令牌以在单个帐户上使用的方法，可以试试这个 - ＆gt; https://coderwall.com/p/cfgneq

我需要一种方法来使用instagram API来获取特定帐户的所有最新媒体。

Answer 7

这是一个铁路解决方案。它是一种后门，实际上就是前门。

# create a headless browser
b = Watir::Browser.new :phantomjs
uri = 'https://www.instagram.com/explore/tags/' + query
uri = 'https://www.instagram.com/' + query if type == 'user'

b.goto uri

# all data are stored on this page-level object.
o = b.execute_script( 'return window._sharedData;')

b.close

您获得的对象取决于它是用户搜索还是标签搜索。我得到这样的数据：

if type == 'user'
  data = o[ 'entry_data' ][ 'ProfilePage' ][ 0 ][ 'user' ][ 'media' ][ 'nodes' ]
  page_info = o[ 'entry_data' ][ 'ProfilePage' ][ 0 ][ 'user' ][ 'media' ][ 'page_info' ]
  max_id = page_info[ 'end_cursor' ]
  has_next_page = page_info[ 'has_next_page' ]
else
  data = o[ 'entry_data' ][ 'TagPage' ][ 0 ][ 'tag' ][ 'media' ][ 'nodes' ]
  page_info = o[ 'entry_data' ][ 'TagPage' ][ 0 ][ 'tag' ][ 'media' ][ 'page_info' ]
  max_id = page_info[ 'end_cursor' ]
  has_next_page = page_info[ 'has_next_page' ]
end

然后我通过以下方式构建网址来获得另一页结果：

  uri = 'https://www.instagram.com/explore/tags/' + query_string.to_s\
    + '?&max_id=' + max_id.to_s
  uri = 'https://www.instagram.com/' + query_string.to_s + '?&max_id='\
    + max_id.to_s if type === 'user'

Answer 8

感谢Instagram不断变化（以及可怕的设计）API架构，上述大部分内容将不再适用于2018年4月。

如果您使用https://www.instagram.com/username/?__a=1方法直接查询其API，则以下是访问单个帖子数据的最新路径。

假设您返回的JSON数据为$data，您可以使用以下路径示例循环显示每个结果：

foreach ($data->graphql->user->edge_owner_to_timeline_media->edges as $item) {

    $content_id = $item->node->id; 
    $date_posted = $item-node->taken_at_timestamp;
    $comments = $item->node->edge_media_to_comment->count;
    $likes = $item->node->edge_liked_by->count;
    $image = $item->node->display_url;
    $content = $item->node->edge_media_to_caption->edges[0]->node->text;
    // etc etc ....
}

最近这一变化的主要内容是graphql和edge_owner_to_timeline_media。

对于非商业用户来说，他们似乎要杀掉这个API访问权限。 {{3}}中的客户尽可能充分利用它。

希望它对某人有所帮助;）

Answer 9

只想加入@ 350D答案，因为我很难理解。

我的代码逻辑是下一个：

第一次调用API时，我只调用https://www.instagram.com/_vull_ /media/。当我收到回复时，我检查more_available的布尔值。如果是真的，我从数组中获取最后一张照片，获取其ID，然后再次调用Instagram API，但这次是https://www.instagram.com/_vull_/media/?max_id=1400286183132701451_1642962433。

重要的是要知道，这个Id是数组中最后一张图片的Id。因此，当要求maxId使用数组中图片的最后一个id时，您将获得接下来的20张图片，依此类推。

希望这能澄清事情。

Answer 10

如果您绕过Oauth，您可能不知道他们是哪个Instagram用户。话虽如此，有几种方法可以在没有身份验证的情况下获取Instagram图像。

Instagram的API允许您在不进行身份验证的情况下查看用户最受欢迎的图像。使用以下端点：Here is link
Instagram在this处为标签提供RSS订阅源。
Instagram用户页面是公开的，因此您可以使用PHP和CURL来获取他们的页面和DOM解析器来搜索html以获取您想要的图像标记。

Answer 11

还有一个技巧，就是按标签搜索照片：

final String url = "connectioninfo";
final String username = "user";
final String password = "password";

try {
    Connection conn = DriverManager.getConnection(url, username, password);

     String sql = "SELECT document_id, file_name, data FROM documents WHERE file_name like '%.doc'";
     PreparedStatement stmt = conn.prepareStatement(sql);
     ResultSet resultSet = stmt.executeQuery();

     while (resultSet.next()) {
          String da_document_id = resultSet.getString(1);
          String file_name = resultSet.getString(2);

          File data = new File("c:\\databaseDoc.doc");
          FileOutputStream fos = new FileOutputStream(data);

          byte[] buffer = new byte[1];
          InputStream is = resultSet.getBinaryStream(3);
          try {
            while (is.read(buffer) > 0) {
                fos.write(buffer);
            }
            fos.close();
            } catch (IOException e) {
                e.printStackTrace();
        }


        System.out.println("da_document_id= " + da_document_id);
        System.out.println("file_name= " + file_name);
    }
    conn.close();

    } catch (SQLException e) {
        e.printStackTrace();
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    }

其中：

GET https://www.instagram.com/graphql/query/?query_hash=3e7706b09c6184d5eafd8b032dbcf487&variables={"tag_name":"nature","first":25,"after":""} - 永久价值（我相信它的散列17888483320059182，将来可以更改）

query_hash - 标题不言自明

tag_name - 要获取的项目数量（我不知道原因，但此值无法按预期工作。实际返回的照片数量略大于值乘以4.5（约为110）值为25，值为100）约为460））

first - 如果您想从该ID获取项目，则为最后一项的ID。可以在此处使用来自JSON响应的after的值。

Answer 12

好吧，当/?__a=1现在停止工作时，最好使用curl并解析Instagram页面，如下所示：Generate access token Instagram API, without having to log in?

Answer 13

<强>更新

这种方法不再适用

JSFiddle

使用Javascript：

$(document).ready(function(){

    var username = "leomessi";
    var max_num_items = 5;

    var jqxhr = $.ajax( "https://www.instagram.com/"+username+"/?__a=1" ).done(function() {
        //alert( "success" );
    }).fail(function() {
        //alert( "error" );
    }).always(function(data) {
        //alert( "complete" )
        items = data.graphql.user.edge_owner_to_timeline_media.edges;
        $.each(items, function(n, item) {
            if( (n+1) <= max_num_items )
            {
                var data_li = "<li><a target='_blank' href='https://www.instagram.com/p/"+item.node.shortcode+"'><img src='" + item.node.thumbnail_src + "'/></a></li>";
                $("ul.instagram").append(data_li);
            }
        });

    });

});

HTML：

<ul class="instagram">
</ul>

CSS：

ul.instagram {
    list-style: none;
}

ul.instagram li {
  float: left;
}

ul.instagram li img {
    height: 100px;
}

Answer 14

您可以使用此API检索instagram用户的公共信息：
https://api.lityapp.com/instagrams/thebrainscoop?limit=2

如果您未设置limit参数，则默认情况下帖子数限制为12

如您在代码中所见，此api是在SpringBoot中使用HtmlUnit制作的：

public JSONObject getPublicInstagramByUserName(String userName, Integer limit) {
    String html;
    WebClient webClient = new WebClient();

    try {
        webClient.getOptions().setCssEnabled(false);
        webClient.getOptions().setJavaScriptEnabled(false);
        webClient.getOptions().setThrowExceptionOnScriptError(false);
        webClient.getCookieManager().setCookiesEnabled(true);

        Page page = webClient.getPage("https://www.instagram.com/" + userName);
        WebResponse response = page.getWebResponse();

        html = response.getContentAsString();
    } catch (Exception ex) {
        ex.printStackTrace();

        throw new RuntimeException("Ocorreu um erro no Instagram");
    }

    String prefix = "static/bundles/es6/ProfilePageContainer.js";
    String sufix = "\"";
    String script = html.substring(html.indexOf(prefix));

    script = script.substring(0, script.indexOf(sufix));

    try {
        Page page = webClient.getPage("https://www.instagram.com/" + script);
        WebResponse response = page.getWebResponse();

        script = response.getContentAsString();
    } catch (Exception ex) {
        ex.printStackTrace();

        throw new RuntimeException("Ocorreu um erro no Instagram");
    }

    prefix = "l.pagination},queryId:\"";

    String queryHash = script.substring(script.indexOf(prefix) + prefix.length());

    queryHash = queryHash.substring(0, queryHash.indexOf(sufix));
    prefix = "<script type=\"text/javascript\">window._sharedData = ";
    sufix = ";</script>";
    html = html.substring(html.indexOf(prefix) + prefix.length());
    html = html.substring(0, html.indexOf(sufix));

    JSONObject json = new JSONObject(html);
    JSONObject entryData = json.getJSONObject("entry_data");
    JSONObject profilePage = (JSONObject) entryData.getJSONArray("ProfilePage").get(0);
    JSONObject graphql = profilePage.getJSONObject("graphql");
    JSONObject user = graphql.getJSONObject("user");
    JSONObject response = new JSONObject();

    response.put("id", user.getString("id"));
    response.put("username", user.getString("username"));
    response.put("fullName", user.getString("full_name"));
    response.put("followedBy", user.getJSONObject("edge_followed_by").getLong("count"));
    response.put("following", user.getJSONObject("edge_follow").getLong("count"));
    response.put("isBusinessAccount", user.getBoolean("is_business_account"));
    response.put("photoUrl", user.getString("profile_pic_url"));
    response.put("photoUrlHD", user.getString("profile_pic_url_hd"));

    JSONObject edgeOwnerToTimelineMedia = user.getJSONObject("edge_owner_to_timeline_media");
    JSONArray posts = new JSONArray();

    try {
        loadPublicInstagramPosts(webClient, queryHash, user.getString("id"), posts, edgeOwnerToTimelineMedia, limit == null ? 12 : limit);
    } catch (Exception ex) {
        ex.printStackTrace();

        throw new RuntimeException("Você fez muitas chamadas, tente mais tarde");
    }

    response.put("posts", posts);

    return response;
}

private void loadPublicInstagramPosts(WebClient webClient, String queryHash, String userId, JSONArray posts, JSONObject edgeOwnerToTimelineMedia, Integer limit) throws IOException {
    JSONArray edges = edgeOwnerToTimelineMedia.getJSONArray("edges");

    for (Object elem : edges) {
        if (limit != null && posts.length() == limit) {
            return;
        }

        JSONObject node = ((JSONObject) elem).getJSONObject("node");

        if (node.getBoolean("is_video")) {
            continue;
        }

        JSONObject post = new JSONObject();

        post.put("id", node.getString("id"));
        post.put("shortcode", node.getString("shortcode"));

        JSONArray captionEdges = node.getJSONObject("edge_media_to_caption").getJSONArray("edges");

        if (captionEdges.length() > 0) {
            JSONObject captionNode = ((JSONObject) captionEdges.get(0)).getJSONObject("node");

            post.put("caption", captionNode.getString("text"));
        } else {
            post.put("caption", (Object) null);
        }

        post.put("photoUrl", node.getString("display_url"));

        JSONObject dimensions = node.getJSONObject("dimensions");

        post.put("photoWidth", dimensions.getLong("width"));
        post.put("photoHeight", dimensions.getLong("height"));

        JSONArray thumbnailResources = node.getJSONArray("thumbnail_resources");
        JSONArray thumbnails = new JSONArray();

        for (Object elem2 : thumbnailResources) {
            JSONObject obj = (JSONObject) elem2;
            JSONObject thumbnail = new JSONObject();

            thumbnail.put("photoUrl", obj.getString("src"));
            thumbnail.put("photoWidth", obj.getLong("config_width"));
            thumbnail.put("photoHeight", obj.getLong("config_height"));
            thumbnails.put(thumbnail);
        }

        post.put("thumbnails", thumbnails);
        posts.put(post);
    }

    JSONObject pageInfo = edgeOwnerToTimelineMedia.getJSONObject("page_info");

    if (!pageInfo.getBoolean("has_next_page")) {
        return;
    }

    String endCursor = pageInfo.getString("end_cursor");
    String variables = "{\"id\":\"" + userId + "\",\"first\":12,\"after\":\"" + endCursor + "\"}";

    String url = "https://www.instagram.com/graphql/query/?query_hash=" + queryHash + "&variables=" + URLEncoder.encode(variables, "UTF-8");
    Page page = webClient.getPage(url);
    WebResponse response = page.getWebResponse();
    String content = response.getContentAsString();
    JSONObject json = new JSONObject(content);

    loadPublicInstagramPosts(webClient, queryHash, userId, posts, json.getJSONObject("data").getJSONObject("user").getJSONObject("edge_owner_to_timeline_media"), limit);
}

这是一个响应示例：

{
  "id": "290482318",
  "username": "thebrainscoop",
  "fullName": "Official Fan Page",
  "followedBy": 1023,
  "following": 6,
  "isBusinessAccount": false,
  "photoUrl": "https://scontent-gru2-1.cdninstagram.com/vp/447ffd0262082f373acf3d467435f130/5C709C77/t51.2885-19/11351770_612904665516559_678168252_a.jpg",
  "photoUrlHD": "https://scontent-gru2-1.cdninstagram.com/vp/447ffd0262082f373acf3d467435f130/5C709C77/t51.2885-19/11351770_612904665516559_678168252_a.jpg",
  "posts": [
    {
      "id": "1430331382090378714",
      "shortcode": "BPZjtBUly3a",
      "caption": "If I have any active followers anymore; hello! I'm Brianna, and I created this account when I was just 12 years old to show my love for The Brain Scoop. I'm now nearly finished high school, and just rediscovered it. I just wanted to see if anyone is still active on here, and also correct some of my past mistakes - being a child at the time, I didn't realise I had to credit artists for their work, so I'm going to try to correct that post haste. Also; the font in my bio is horrendous. Why'd I think that was a good idea? Anyway, this is a beautiful artwork of the long-tailed pangolin by @chelsealinaeve . Check her out!",
      "photoUrl": "https://scontent-gru2-1.cdninstagram.com/vp/ab823331376ca46136457f4654bf2880/5CAD48E4/t51.2885-15/e35/16110915_400942200241213_3503127351280009216_n.jpg",
      "photoWidth": 640,
      "photoHeight": 457,
      "thumbnails": [
        {
          "photoUrl": "https://scontent-gru2-1.cdninstagram.com/vp/43b195566d0ef2ad5f4663ff76d62d23/5C76D756/t51.2885-15/e35/c91.0.457.457/s150x150/16110915_400942200241213_3503127351280009216_n.jpg",
          "photoWidth": 150,
          "photoHeight": 150
        },
        {
          "photoUrl": "https://scontent-gru2-1.cdninstagram.com/vp/ae39043a7ac050c56d741d8b4355c185/5C93971C/t51.2885-15/e35/c91.0.457.457/s240x240/16110915_400942200241213_3503127351280009216_n.jpg",
          "photoWidth": 240,
          "photoHeight": 240
        },
        {
          "photoUrl": "https://scontent-gru2-1.cdninstagram.com/vp/ae7a22d09e3ef98d0a6bbf31d621a3b7/5CACBBA6/t51.2885-15/e35/c91.0.457.457/s320x320/16110915_400942200241213_3503127351280009216_n.jpg",
          "photoWidth": 320,
          "photoHeight": 320
        },
        {
          "photoUrl": "https://scontent-gru2-1.cdninstagram.com/vp/1439dc72b70e7c0c0a3afcc30970bb13/5C8E2923/t51.2885-15/e35/c91.0.457.457/16110915_400942200241213_3503127351280009216_n.jpg",
          "photoWidth": 480,
          "photoHeight": 480
        },
        {
          "photoUrl": "https://scontent-gru2-1.cdninstagram.com/vp/1439dc72b70e7c0c0a3afcc30970bb13/5C8E2923/t51.2885-15/e35/c91.0.457.457/16110915_400942200241213_3503127351280009216_n.jpg",
          "photoWidth": 640,
          "photoHeight": 640
        }
      ]
    },
    {
      "id": "442527661838057235",
      "shortcode": "YkLJBXJD8T",
      "caption": null,
      "photoUrl": "https://scontent-gru2-1.cdninstagram.com/vp/dc94b38da679826b9ac94ccd2bcc4928/5C7CDF93/t51.2885-15/e15/11327349_860747310663863_2105199307_n.jpg",
      "photoWidth": 612,
      "photoHeight": 612,
      "thumbnails": [
        {
          "photoUrl": "https://scontent-gru2-1.cdninstagram.com/vp/c1153c6513c44a6463d897e14b2d8f06/5CB13ADD/t51.2885-15/e15/s150x150/11327349_860747310663863_2105199307_n.jpg",
          "photoWidth": 150,
          "photoHeight": 150
        },
        {
          "photoUrl": "https://scontent-gru2-1.cdninstagram.com/vp/47e60ec8bca5a1382cd9ac562439d48c/5CAE6A82/t51.2885-15/e15/s240x240/11327349_860747310663863_2105199307_n.jpg",
          "photoWidth": 240,
          "photoHeight": 240
        },
        {
          "photoUrl": "https://scontent-gru2-1.cdninstagram.com/vp/da0ee5b666ab40e4adc1119e2edca014/5CADCB59/t51.2885-15/e15/s320x320/11327349_860747310663863_2105199307_n.jpg",
          "photoWidth": 320,
          "photoHeight": 320
        },
        {
          "photoUrl": "https://scontent-gru2-1.cdninstagram.com/vp/02ee23571322ea8d0992e81e72f80ef2/5C741048/t51.2885-15/e15/s480x480/11327349_860747310663863_2105199307_n.jpg",
          "photoWidth": 480,
          "photoHeight": 480
        },
        {
          "photoUrl": "https://scontent-gru2-1.cdninstagram.com/vp/dc94b38da679826b9ac94ccd2bcc4928/5C7CDF93/t51.2885-15/e15/11327349_860747310663863_2105199307_n.jpg",
          "photoWidth": 640,
          "photoHeight": 640
        }
      ]
    }
  ]
}

Answer 15

以下nodejs代码从Instagram页面中删除流行的图像。函数'ScrapeInstagramPage'负责老化后效应。

var request = require('parse5');
var request = require('request');
var rp      = require('request-promise');
var $       = require('cheerio'); // Basically jQuery for node.js 
const jsdom = require("jsdom");    
const { JSDOM } = jsdom;


function ScrapeInstagramPage (args) {
    dout("ScrapeInstagramPage for username -> " + args.username);
    var query_url = 'https://www.instagram.com/' + args.username + '/';

    var cookieString = '';

    var options = {
        url: query_url,
        method: 'GET',
        headers: {
            'x-requested-with' : 'XMLHttpRequest',
            'accept-language'  : 'en-US,en;q=0.8,pt;q=0.6,hi;q=0.4', 
            'User-Agent'       : 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_4) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.36',
            'referer'          : 'https://www.instagram.com/dress_blouse_designer/',
            'Cookie'           : cookieString,
            'Accept'           : '*/*',
            'Connection'       : 'keep-alive',
            'authority'        : 'www.instagram.com' 
        }
    };


    function dout (msg) {
        if (args.debug) {
            console.log(msg);
        }
    }

    function autoParse(body, response, resolveWithFullResponse) {
        // FIXME: The content type string could contain additional values like the charset. 
        // Consider using the `content-type` library for a robust comparison. 
        if (response.headers['content-type'] === 'application/json') {
            return JSON.parse(body);
        } else if (response.headers['content-type'] === 'text/html') {
            return $.load(body);
        } else {
            return body;
        }
    }

    options.transform = autoParse;


    rp(options)
        .then(function (autoParsedBody) {
            if (args.debug) {
                console.log("Responce of 'Get first user page': ");
                console.log(autoParsedBody);
                console.log("Creating JSDOM from above Responce...");
            }

            const dom = new JSDOM(autoParsedBody.html(), { runScripts: "dangerously" });
            if (args.debug) console.log(dom.window._sharedData); // full data doc form instagram for a page

            var user = dom.window._sharedData.entry_data.ProfilePage[0].user;
            if (args.debug) {
                console.log(user); // page user
                console.log(user.id); // user ID
                console.log(user.full_name); // user full_name
                console.log(user.username); // user username
                console.log(user.followed_by.count); // user followed_by
                console.log(user.profile_pic_url_hd); // user profile pic
                console.log(autoParsedBody.html());
            }

            if (user.is_private) {
                dout ("User account is PRIVATE");
            } else {
                dout ("User account is public");
                GetPostsFromUser(user.id, 5000, undefined);
            }
        })
        .catch(function (err) {
            console.log( "ERROR: " + err );
        });  

    var pop_posts = [];
    function GetPostsFromUser (user_id, first, end_cursor) {
        var end_cursor_str = "";
        if (end_cursor != undefined) {
            end_cursor_str = '&after=' + end_cursor;
        }

        options.url = 'https://www.instagram.com/graphql/query/?query_id=17880160963012870&id=' 
                        + user_id + '&first=' + first + end_cursor_str;

        rp(options)
            .then(function (autoParsedBody) {
                if (autoParsedBody.status === "ok") {
                    if (args.debug) console.log(autoParsedBody.data);
                    var posts = autoParsedBody.data.user.edge_owner_to_timeline_media;

                    // POSTS processing
                    if (posts.edges.length > 0) {
                        //console.log(posts.edges);
                        pop_posts = pop_posts.concat
                        (posts.edges.map(function(e) {
                            var d = new Date();
                            var now_seconds = d.getTime() / 1000;

                            var seconds_since_post = now_seconds - e.node.taken_at_timestamp;
                            //console.log("seconds_since_post: " + seconds_since_post);

                            var ageing = 10; // valuses (1-10]; big value means no ageing
                            var days_since_post = Math.floor(seconds_since_post/(24*60*60));
                            var df = (Math.log(ageing+days_since_post) / (Math.log(ageing)));
                            var likes_per_day = (e.node.edge_liked_by.count / df);
                            // console.log("likes: " + e.node.edge_liked_by.count);
                            //console.log("df: " + df);
                            //console.log("likes_per_day: " + likes_per_day);
                            //return (likes_per_day > 10 * 1000);
                            var obj = {};
                            obj.url = e.node.display_url;
                            obj.likes_per_day = likes_per_day;
                            obj.days_since_post = days_since_post;
                            obj.total_likes = e.node.edge_liked_by.count;
                            return obj;
                        }
                        ));

                        pop_posts.sort(function (b,a) {
                          if (a.likes_per_day < b.likes_per_day)
                            return -1;
                          if (a.likes_per_day > b.likes_per_day)
                            return 1;
                          return 0;
                        });

                        //console.log(pop_posts);

                        pop_posts.forEach(function (obj) {
                            console.log(obj.url);
                        });
                    }

                    if (posts.page_info.has_next_page) {
                        GetPostsFromUser(user_id, first, posts.page_info.end_cursor);
                    }
                } else {
                    console.log( "ERROR: Posts AJAX call not returned good..." );
                }
            })
            .catch(function (err) {
                console.log( "ERROR: " + err );
            }); 
    }
}


ScrapeInstagramPage ({username : "dress_blouse_designer", debug : false});

试试here

实施例：对于给定的URL“https://www.instagram.com/dress_blouse_designer/”，可以调用函数

ScrapeInstagramPage ({username : "dress_blouse_designer", debug : false});

Answer 16

除了Wordpress，我确实需要此功能。我适合并且效果很好

<script>
    jQuery(function($){
        var name = "caririceara.comcariri";
        $.get("https://images"+~~(Math.random()*33)+"-focus-opensocial.googleusercontent.com/gadgets/proxy?container=none&url=https://www.instagram.com/" + name + "/", function(html) {
            if (html) {
                var regex = /_sharedData = ({.*);<\/script>/m,
                  json = JSON.parse(regex.exec(html)[1]),
                  edges = json.entry_data.ProfilePage[0].graphql.user.edge_owner_to_timeline_media.edges;
              $.each(edges, function(n, edge) {
                   if (n <= 7){
                     var node = edge.node;
                    $('.img_ins').append('<a href="https://instagr.am/p/'+node.shortcode+'" target="_blank"><img src="'+node.thumbnail_src+'" width="150"></a>');
                   }
              });
            }
        });
    }); 
    </script>

Answer 17

这可以使用简单的ajax调用和迭代图像路径。

        var name = "nasa";
        $.get("https://www.instagram.com/" + name + "/?__a=1", function (data, status) {
            console.log('IG_NODES', data.user.media.nodes);
            $.each(data.user.media.nodes, function (n, item) {
                console.log('ITEMS', item.display_src);
                $('body').append(
                    "<div class='col-md-4'><img class='img-fluid d-block' src='" + item.display_src + "'></div>"
                );
            });
        })

Answer 18

如果您要搜索没有clientID和访问令牌的用户：

1：如果要搜索名称与搜索词相似的所有用户：

用您要搜索的文本替换SeachName：

https://www.instagram.com/web/search/topsearch/?query=SearchName

2：如果要搜索完全相同的用户名：

用所需的搜索名称替换用户名：

https://www.instagram.com/UserName/?__a=1

Answer 19

这是一个PHP脚本，可下载图像并创建带有图像链接的html文件。信誉350D为php版本，这只是详细说明了。我建议您将其作为一项Cron工作，并根据需要经常解雇。 从2019年5月起已通过验证。

<?
$user = 'smena8m';
$igdata = file_get_contents('https://instagram.com/'.$user.'/');
preg_match('/_sharedData = ({.*);<\/script>/',$igdata,$matches);
$profile_data = json_decode($matches[1])->entry_data->ProfilePage[0]->graphql->user;
$html = '<div class="instagramBox" style="display:inline-grid;grid-template-columns:auto auto auto;">';
$i = 0;
$max = 9;
while($i<$max){
    $imglink = $profile_data->edge_owner_to_timeline_media->edges[$i]->node->shortcode;
    $img = $profile_data->edge_owner_to_timeline_media->edges[$i]->node->thumbnail_resources[0]->src;
    file_put_contents('ig'.$i.'.jpg',file_get_contents($img));
    $html .= '<a href="https://www.instagram.com/p/'.$imglink.'/" target="_blank"><img src="ig'.$i.'.jpg" /></a>';
    $i++;
}
$html .= '</div>';
$instagram = fopen('instagram.html','w');
fwrite($instagram,$html);
fclose($instagram);
?>

如何在不验证用户身份的情况下从Instagram获取用户的媒体？

19 个答案: