我在“大”文件(大约4Mb)上做了一些操作
我这样做: 1.从目录中获取所有文件并将它们放在IList中MyInfoClass具有以下属性:name,extension,fullPath,creationDate,contentPart 2.我做一个Linq查询只获得一些扩展类型。 3.我循环查询Linq查询结果,每次打开文件,执行一些操作(获取值)并将结果放入MyFileIno.ContentPart。
仅供参考:30个文件,这是14秒的操作
这是工作。
问题是,当我从UI运行我的库时,当我单击按钮时,窗口在操作期间冻结。我想:
你能给我解决这类问题的最佳做法吗?
谢谢,
代码
public class FileManager
{
public string CurrentFileName { get; set; }
public void Validation(string path)
{
IList<InfoFile> listFile = GetListFile(path);
foreach (InfoFile item in listFile)
{
CurrentFileName = item.Name;
.....
}
}
}
private void button1_Click(object sender, EventArgs e)
{
var worker = new BackgroundWorker();
worker.DoWork += (s, args) =>
{
int percentProgress = 6;
FileManager fileManager = new FileManager();
fileManager.Validation(@"C:.....");
((BackgroundWorker)s).ReportProgress(percentProgress, fileManager.CurrentFileName);
};
worker.ProgressChanged += (s, args) =>
{
var currentFilename = (string)args.UserState;
label1.Text = currentFilename;
progressBar1.Value = args.ProgressPercentage;
};
worker.RunWorkerCompleted += (s, args) =>
{
progressBar1.Value = 0;
};
worker.RunWorkerAsync();
}
答案 0 :(得分:17)
应用程序冻结,因为您正在主线程中执行文件解析。您可以使用BackgroundWorker在新线程上执行操作。这里有一些伪代码可以帮助您入门:
private void button1_Click(object sender, EventArgs e)
{
var worker = new BackgroundWorker();
worker.DoWork += (s, args) =>
{
// Here you perform the operation and report progress:
int percentProgress = ...
string currentFilename = ...
((BackgroundWorker)s).ReportProgress(percentProgress, currentFilename);
// Remark: Don't modify the GUI here because this runs on a different thread
};
worker.ProgressChanged += (s, args) =>
{
var currentFilename = (string)args.UserState;
// TODO: show the current filename somewhere on the UI and update progress
progressBar1.Value = args.ProgressPercentage;
};
worker.RunWorkerCompleted += (s, args) =>
{
// Remark: This runs when the DoWork method completes or throws an exception
// If args.Error != null report to user that something went wrong
progressBar1.Value = 0;
};
worker.RunWorkerAsync();
}