https://github.com/nadavfima/cardsui-for-android
我正在使用这个库在内容中创建一个带有简单标题和更复杂的列表视图的卡片。我遇到的问题是我无法从文件“card_ex.xml”访问任何xml对象,因为“错误”视图被设置为内容视图。
MainActivity.java
package com.cardsui.example;
import android.app.Activity;
import android.content.Context;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.Menu;
import android.view.View;
import android.widget.ArrayAdapter;
import android.widget.ListView;
import android.widget.RelativeLayout;
import com.fima.cardsui.views.CardUI;
public class MainActivity extends Activity {
ListView lv;
private CardUI mCardView;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
// init CardView
mCardView = (CardUI) findViewById(R.id.cardsview);
mCardView.setSwipeable(false);
MyCard idag = new MyCard("Idag");
idag.getView(this);
// add one card, and then add another one to the last stack.
mCardView.addCard(new MyCard("Idag"));
lv = (ListView) findViewById(android.R.id.item_list);
String[] items = new String[] {"Item 1", "Item 2", "Item 3", "Item 4", "Item 5", "Item 6", "Item 7"};
ArrayAdapter<String> adapter =
new ArrayAdapter<String>(this, android.R.layout.select_dialog_singlechoice, items);
// lv.setAdapter(adapter);
// draw cards
mCardView.refresh();
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.activity_main, menu);
return true;
}
}
card_ex.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="vertical"
android:paddingBottom="16dp" >
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:gravity="center_vertical"
android:paddingLeft="8dp"
android:paddingRight="8dp" >
<TextView
android:id="@+id/title"
style="@style/CardTitle"
android:layout_width="0dp"
android:layout_height="wrap_content"
android:layout_weight="1"
android:text="title" />
</LinearLayout>
<View
android:layout_width="fill_parent"
android:layout_height="1dp"
android:layout_marginTop="4dp"
android:background="@color/stroke" />
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:background="@drawable/selectable_background_cardbank"
android:gravity="center_vertical"
android:padding="4dp" >
<ListView
android:id="@+id/item_list"
style="@style/CardText"
android:layout_width="wrap_content"
android:layout_height="400dp"
android:divider="@color/stroke"
android:dividerHeight="1dp"
android:ellipsize="end" />
</LinearLayout>
</LinearLayout>
activity_main.xml中
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="@drawable/background"
android:id="@+id/cards">
<com.fima.cardsui.views.CardUI
android:id="@+id/cardsview"
android:layout_width="match_parent"
android:layout_height="match_parent" />
</RelativeLayout>
我想操作不在内容视图中的id“item_list”,而是在另一个xml文件“card_ex”中操作。
无论如何我可以在当前设置的内容视图中找到一个ID吗?