所以,我需要帮助在子查询中做一个选择,我知道这有点基础,但我还是不能自己做。
(Reparacao =维修和lojas =商店,从葡萄牙语到英语)
我想获得每家商店的维修数量。但是我一次只能做一个商店,但我想要一个选择所有商店的查询。
我正在使用此查询:
SELECT COUNT( DISTINCT id_reparacao ) , lojas.nome
FROM reparacoes
INNER JOIN lojas ON lojas.id = 1
WHERE id_loja = lojas.id
我想要这样的东西:
SELECT COUNT( DISTINCT id_reparacao ) , lojas.nome
FROM reparacoes
INNER JOIN lojas ON lojas.id = (Select id from lojas) //i want the id of every store
WHERE id_loja = lojas.id
答案 0 :(得分:1)
试试这个:
无需使用子查询来获取商店的所有修复计数。 您可以使用 JOIN 和 GROUP BY 轻松获得结果。
SELECT COUNT(DISTINCT id_reparacao) repairCnt, lojas.nome
FROM reparacoes
INNER JOIN lojas ON lojas.id = id_loja
GROUP BY lojas.id
答案 1 :(得分:0)
为什么不尝试加入ON
ID:
SELECT COUNT( DISTINCT r.id_reparacao ) , lojas.nome
FROM reparacoes r
INNER JOIN lojas l ON l.id = r.id_loja;