Question

基本上我有一个名为site.php的contreller，并且有视图：header.php，nav.php，content.php，footer.php等问题是怎么运行content_about.php的？我正在尝试这个网址：网站/关于但我在浏览器上收到错误！代码是：

<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');

class site extends CI_Controller {

    public function index()
    {
        $this->home();
    }
    public function home()
    {
        $this->load->view("site_header");
        $this->load->view("site_nav");
        $this->load->view("content_home");
        $this->load->view("site_footer");
    }
    public function about()
    {
        $this->load->view("site_header");
        $this->load->view("site_nav");
        $this->load->view("content_about");
        $this->load->view("site_footer");
    }
}

Answer 1

试试这个。

public function about()
{
    $data=array();
    $data['main']='content_about'; //only the content part without header,nav and footer
    $this->load->view('template',$data);
}

在视图中make template.php并放置这行

<?=$this->load->view('site_header.php');?>
<?=$this->load->view('site_nav.php');?>
<?=$this->load->view($main);?>
<?=$this->load->view('site_footer');?>

如果您遇到任何问题，请告诉我。

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1 个答案: