1 2:select(table。*)/(all column)没问题
String sql = "select t_student.* from t_student";
//String sql = "select t_student.id,t_student.name,... from t_student"; //select all column
SQLQuery query = session.createSQLQuery(sql);
query.addEntity(Student.class);//or query.addEntity("alias", Student.class);
//query.list();[Student@..., Student@..., Student@...]
query.setResultTransformer(Transformers.ALIAS_TO_ENTITY_MAP); //or other transformer
query.list(); //[{Student(or alias)=Student@...},{Student=Student@...}]
3:选择一些列(不是全部),是错误
String sql = "select t_student.id,t_student.name.t_student.sex from t_student";
SQLQuery query = session.createSQLQuery(sql);
query.addEntity(Student.class);
query.setResultTransformer(Transformers.ALIAS_TO_ENTITY_MAP);
query.list(); //Exception:invalid column/no column
我希望“3”正常工作,并将结果映射到Student.class
喜欢:学生[id = ?, name =?,sex =?,(其他字段为null /默认)]
我不知道这个错误,请帮帮我!
答案 0 :(得分:21)
你可以进一步添加
.setResultTransformer(Transformers.aliasToBean(YOUR_DTO.class));
并自动将其映射到您的自定义dto对象,另请参阅Returning non-managed entities。
例如:
public List<MessageExtDto> getMessagesForProfile2(Long userProfileId) {
Query query = getSession().createSQLQuery(" "
+ " select a.*, b.* "
+ " from messageVO AS a "
+ " INNER JOIN ( SELECT max(id) AS id, count(*) AS count FROM messageVO GROUP BY messageConversation_id) as b ON a.id = b.id "
+ " where a.id > 0 "
+ " ")
.addScalar("id", new LongType())
.addScalar("message", new StringType())
......... your mappings
.setResultTransformer(Transformers.aliasToBean(MessageExtDto.class));
List<MessageExtDto> list = query.list();
return list;
}
答案 1 :(得分:3)
只有两种方式。
您可以使用第一个或第二个代码段。根据Hibernate文档,您必须更喜欢2nd。
您只能得到一个对象数组列表,如下所示:
String sql = "select name, sex from t_student";
SQLQuery query = session.createSQLQuery(sql);
query.addScalar("name", StringType.INSTANCE);
query.addScalar("sex", StringType.INSTANCE);
query.list();
答案 2 :(得分:3)
我想&#34; 3&#34;工作正常,让结果可以映射到Student.class
可以使用
Query createNativeQuery(String sqlString, String resultSetMapping
)
在第二个参数中,您可以告诉结果映射的名称。例如:
1)让我们考虑一个学生实体,魔法将在SqlResultSetMapping注释中:
import javax.persistence.Entity;
import javax.persistence.SqlResultSetMapping;
import javax.persistence.Table;
@Entity
@Table(name = "student")
@SqlResultSetMapping(name = "STUDENT_MAPPING", classes = {@ConstructorResult(
targetClass = Student.class, columns = {
@ColumnResult(name = "name"),
@ColumnResult(name = "address")
})})
public class Student implements Serializable {
private String name;
private String address;
/* Constructor for the result mapping; the key is the order of the args*/
public Student(String aName, String anAddress) {
this.name = aName;
this.address = anAddress;
}
// the rest of the entity
}
2)现在您可以执行查询,结果将由STUDENT_MAPPING
逻辑映射:
String query = "SELECT s FROM student s";
String mapping = "STUDENT_MAPPING";
Query query = myEntityManager.createNativeQuery(query, mapping);
@SuppressWarnings("unchecked")
List<Student> students = query.getResultList();
for (Student s : students) {
s.getName(); // ...
}
注意:我认为无法避免未经检查的警告。
答案 3 :(得分:1)
我在HQL查询上遇到了同样的问题。我通过更换变压器解决了这个问题。
问题导致编写的代码转换为Map。但它不适合Alias Bean。您可以在下面看到错误代码。编写的代码将结果显示为map并将新字段添加到地图中。
类:org.hibernate.property.access.internal.PropertyAccessMapImpl.SetterImpl 米 方法:设置
@Override
@SuppressWarnings("unchecked")
public void set(Object target, Object value, SessionFactoryImplementor factory) {
( (Map) target ).put( propertyName, value );
}
我解决了复制变换器和更改代码的问题。
您可以在项目中看到代码。
类别:
import java.lang.reflect.Field;
import java.util.Map;
import io.robe.hibernate.criteria.api.query.SearchQuery;
import org.hibernate.HibernateException;
import org.hibernate.transform.AliasedTupleSubsetResultTransformer;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
public class AliasToBeanResultTransformer extends AliasedTupleSubsetResultTransformer {
private static final Logger LOGGER = LoggerFactory.getLogger(AliasToBeanResultTransformer.class);
private final Class resultClass;
// Holds fields of Transform Class as Map. Key is name of field.
private Map<String, Field> fieldMap;
public AliasToBeanResultTransformer(Class resultClass) {
if ( resultClass == null ) {
throw new IllegalArgumentException( "resultClass cannot be null" );
}
fieldMap = SearchQuery.CacheFields.getCachedFields(resultClass);
this.resultClass = resultClass;
}
@Override
public boolean isTransformedValueATupleElement(String[] aliases, int tupleLength) {
return false;
}
@Override
public Object transformTuple(Object[] tuple, String[] aliases) {
Object result;
try {
result = resultClass.newInstance();
for ( int i = 0; i < aliases.length; i++ ) {
String name = aliases[i];
Field field = fieldMap.get(name);
if(field == null) {
LOGGER.error(name + " field not found in " + resultClass.getName() + " class ! ");
continue;
}
field.set(result, tuple[i]);
}
}
catch ( InstantiationException e ) {
throw new HibernateException( "Could not instantiate resultclass: " + resultClass.getName() );
} catch ( IllegalAccessException e ) {
throw new HibernateException( "Could not instantiate resultclass: " + resultClass.getName() );
}
return result;
}
}
创建新Transformer之后您可以使用如下所示。
query.setResultTransformer(new AliasToBeanResultTransformer(YOUR_DTO.class));
答案 4 :(得分:0)
您可以自动映射它:
您的模型 Student.java
公开课学生{ 私人字符串名称; 私有字符串地址; }
存储库
String sql = "Select * from student"; 查询查询 = em.createNativeQuery(sql, Student.class); List ls = query.getResultList();