Question

修复了代码，但最后仍显示错误。 public void displayCharacterDetails()的位置。

public class Character
{
    private string char_name;
    private string char_descr;
    private byte char_level;
    private byte char_attack;
    private byte char_defence;
    private bool char_defeat;

    public Character(string name, string desc, byte level, byte attack, byte defence, bool defeat)
    {
        char_name = name;
        char_descr = "";
        char_level = level;
        char_attack = attack;
        char_defence = defence;
        char_defeat = defeat;
    }

    public string GetCharacterName()
    {
        return char_name;
    }

    public string GetCharacterDescription()
    {
        return char_descr;
    }

    public void SetCharacterDescription(string descr)
    {
        char_descr = descr;
    }

    public byte GetCharLevel()
    {
        return char_level;
    }

    public byte GetCharacterAttack()
    {
        return char_attack;
    }



    public byte GetCharacterDefence()
    {

        return char_defence;

    }

    public void resetCharacter(string name, string descr, byte level, byte attack, byte defence, bool defeat)
    {
        char_name = name;
        char_descr = "";
        char_level = level;
        char_attack = attack;
        char_defence = defence;
        char_defeat = defeat;
    }

    public void displayCharacterDetails() 

    { 

System.out.println("Character name: " + char_name); 

System.out.println("Character description" + char_descr); 

System.out.println("Character Level, Attack, Defence: " + char_level + " ,"+ char_attack + "  ,"+ char_defence);  
    }

}

Answer 1

将第一行替换为：

public Character(string char_name, string char_desc, byte char_level, byte char_attack, byte char_defence, bool char_defeat)

从方法声明中删除;。

此外，你在这里错过了一个结束括号：

public byte getCharacterAttack() 

{

而且，您不能将方法命名为私有字段。

您有一个名为char_level的字段（如您的构造函数中显示this.char_level）和此处具有相同名称的方法：

public byte char_level() 

{ 

return char_level; 

}

重命名字段或解决该问题的方法。

最后，在你的构造函数中，你有一个名为lkike byte char_level的参数，但你做this.char_level = level;。将this.char_level = char_level;替换为每个参数，或者只调用每个参数byte level。

所以基本上你应该有这个：

public class Character
{
    private string char_name;
    private string char_descr;
    private byte char_level;
    private byte char_attack;
    private byte char_defence;
    private bool char_defeat;

    public Character(string name, string desc, byte level, byte attack, byte defence,
                     bool defeat)
    {
        char_name = name;
        char_descr = "";
        char_level = level;
        char_attack = attack;
        char_defence = defence;
        char_defeat = defeat;
    }

    public string GetCharacterName()
    {
        return char_name;
    }

    public string GetCharacterDescription()
    {
        return char_descr;
    }

    public void SetCharacterDescription(string descr)
    {
        char_descr = descr;
    }

    public byte GetCharLevel()
    {
        return char_level;
    }

    public byte GetCharacterAttack()
    {
        return char_attack;
    }
}

我将您的方法重命名为遵循C＃约定。我还删除了this关键字，这些参数名称不需要它。另外请避免在你的留置权之间留下太多的空白，这很难读懂。

或者你可以简单地使用C＃属性：

public class Character
{
    public string Name { get; set; }
    public string Descr { get; set; }
    public byte Level { get; set; }
    public byte Attack { get; set; }
    public byte Defence { get; set; }
    public bool Defeat { get; set; }
{

并创建新的字符：

Character character = new Character { Name = "the name", Descr = "the descr" } //etc.

Answer 2

删除末尾的分号;。

public Character(string char_name, string char_desc, byte char_level, 
byte char_attack, 
byte char_defence, bool char_defeat);   //<< - remove the semicolon

Answer 3

public Character(string char_name, string char_desc, byte char_level,  
     byte char_attack, byte char_defence, bool char_defeat);

不是你如何声明构造函数。你想要这个：

public Character(string char_name, string char_desc, byte char_level,  
     byte char_attack, byte char_defence, bool char_defeat)  
{  
   ...  
}

注意删除分号;

Answer 4

你的赋值向后看，如果你传入一个名为char_name的参数，看起来你有一个名为name的类字段，构造函数中的代码行应该是this.name = char_name;您的set方法中存在同样的问题。

Answer 5

在构造函数后面加了一个分号。

错误：预期的类，委托，枚举，接口或结构

5 个答案: