Question

以下是我的表格：

auth_keys ：

id    /    keys    / user 
1     /    12345   /   1

* 产品* ：

id    / company    /   name
1     /  1         /   iphone
2     /  2         /   iphone

公司：

id    / name       /   mkey
1     / myComp     /   54321

这是我的sql请求：

SELECT 
    products.id_product AS id_product, 
    auth_keys.keys AS vkey,
    auth_keys.user AS user_id
FROM 
    auth_keys
JOIN 
    products
LEFT JOIN 
    companies ON products.company = companies.id
WHERE 
    products.name_product = "iphone"
    AND companies.mkey = "54321" 
HAVING 
    vkey = "none"

我想做的事情：

我id_products获得id_company然后获得name_product，因为我可以为两家不同的公司提供同名产品。这部分没问题。
我想要user_key值WHERE keys = "12345" OR "NONE"，这就是我的问题。如果keys =“12345”，一切都有效，但如果key =“none / nothing”，我什么也得不到......

我想得到第一个结果，id_product，即使我无法匹配user_key ...

感谢您的帮助！

Answer 1

试试这个：


    SELECT 
    products.id_product AS id_product, 
    auth_keys.keys AS vkey,
    auth_keys.user AS user_id
    FROM auth_keys
    JOIN products
    LEFT JOIN companies ON products.company = companies.id
    WHERE 
    products.name_product = "iphone"
    AND (companies.mkey = "54321"or vkey = "none")

不需要与“group by”子句一起使用的“having”来过滤聚合结果。

Answer 2

我真的很难理解表格如何结合在一起。您似乎希望在没有任何条件的情况下加入auth_keys，除非密钥必须是12345或NONE。如果两者都匹配，不确定你想要什么。

然而快速尝试

SELECT products.id_product AS id_product, 
    auth_keys.keys AS vkey,
    auth_keys.user AS user_id
FROM products
LEFT OUTER JOIN companies
ON products.company = companies.id
AND companies.mkey = "54321"
LEFT OUTER JOIN auth_keys
ON auth_keys.keys IN ('12345', 'NONE')
WHERE products.name_product = "iphone"

SQL不同的关节和WHERE子句可能是错误的

2 个答案: