ID RANGE_ID START_DATE END_DATE BAND_TYPE FLAG_LINE
3 1 01/03/2013 31/03/2013 R 1
4 1 01/03/2013 31/03/2013 R 0
5 2 01/03/2013 31/03/2013 R 1
6 2 01/03/2013 31/03/2013 R 0
7 3 01/03/2013 31/03/2013 R 0
8 3 01/03/2013 31/03/2013 N 0
从这个表中,对于每个RANGE_ID,我需要使用以下条件选择行: 如果有相同列的行(除了ID字段),那么只选择FLAG_LINE = 1的行,如果有相同的行,但没有一行包含FLAG_LINE = 1列,则选择所有列,基于此查询应返回以下结果:
ID RANGE_ID START_DATE END_DATE BAND_TYPE FLAG_LINE
3 1 01/03/2013 31/03/2013 R 1
5 2 01/03/2013 31/03/2013 R 1
7 3 01/03/2013 31/03/2013 R 0
8 3 01/03/2013 31/03/2013 N 0
我尝试以块的形式进行操作:即为每个RANGE运行类似的东西:
begin
for x in ( select count(*) cnt
from dual
where exists (
select 1 FROM myTable
WHERE RANGE_ID = 1 AND FLAG_LINE = 1) )
loop
if ( x.cnt = 1 )
then
dbms_output.put_line('flag line exists');
--insert the line with FLAG_LINE = 1 into temp table for this range
else
dbms_output.put_line('does not exist');
--insert the lines into temp table for this range
end if;
end loop;
end;
为每个RANGE使用此方法我填充临时表并在结尾返回结果,但这不是很灵活,还有另一种方法可以实现吗?
由于
答案 0 :(得分:2)
尝试这样......
Select * from tablename where flag=1
union
(Select * from tablename a where (Select count(*) from tablename b
where a.Range_id=b.RANGE_ID and b.flag=1)<1)
答案 1 :(得分:0)
试试这个。
select * from myTable
where flag_line = 1
or
(range_id, start_date, end_date, band_type) in (
select range_id, start_date, end_date, band_type
from myTable
group by range_id, start_date, end_date, band_type
having max(flag_line) = 0)
答案 2 :(得分:0)
这是获得您想要的结果的另一种方式
SELECT *
FROM info
WHERE flag_line = 1
UNION
SELECT *
FROM info i1
WHERE NOT EXISTS (SELECT NULL
FROM info i2
WHERE i2.range_id = i1.range_id
AND i2.flag_line = 1
)