Question

目前，我有3个阵列。我想要几个小时。我可以以任何动态方式实现此功能。对我来说For循环不起作用。有没有办法动态实现这个。如果你们帮忙解决这个问题，我将很高兴。

 switch(pageNumber){
            case 0:
                final ListView list1 = (ListView)rootView.findViewById(R.id.list);
                BinderData bindingData = new BinderData(this.getActivity(), d[0]);
                list1.setAdapter(bindingData);
                list1.setOnItemClickListener(new OnItemClickListener() {
                    @Override
                    public void onItemClick(AdapterView<?> a, View v, int position, long id) {
                        if (d[0].get(position).getItemType() == 0
                                || d[0].get(position).getItemType() == 3
                                || d[0].get(position).getItemType() == 2)
                            return;
                        Intent intent = new Intent(Schedule.this.getActivity(),
                                ContentExtended.class);
                        intent.putExtra("title", d[0].get(position).getTitle());
                        intent.putExtra("content", d[0].get(position).getContent());
                        startActivity(intent);
                    }
                });
                break;
            case 1:
                final ListView list2 = (ListView)rootView.findViewById(R.id.list);
                BinderData bindingData1 = new BinderData(this.getActivity(), d[1]);
                list2.setAdapter(bindingData1);
                list2.setOnItemClickListener(new OnItemClickListener() {
                    @Override
                    public void onItemClick(AdapterView<?> a, View v, int position, long id) {
                        if (d[1].get(position).getItemType() == 0
                                || d[1].get(position).getItemType() == 3
                                || d[1].get(position).getItemType() == 2)
                            return;
                        Intent intent = new Intent(Schedule.this.getActivity(),
                                ContentExtended.class);
                        intent.putExtra("title", d[1].get(position).getTitle());
                        intent.putExtra("content", d[1].get(position).getContent());
                        startActivity(intent);
                    }
                });
                break;
            case 2:
                final ListView list3 = (ListView)rootView.findViewById(R.id.list);
                BinderData bindingData2 = new BinderData(this.getActivity(), d[2]);
                list3.setAdapter(bindingData2);
                list3.setOnItemClickListener(new OnItemClickListener() {
                    @Override
                    public void onItemClick(AdapterView<?> a, View v, int position, long id) {
                        if (d[2].get(position).getItemType() == 0
                                || d[2].get(position).getItemType() == 3
                                || d[2].get(position).getItemType() == 2)
                            return;
                        Intent intent = new Intent(Schedule.this.getActivity(),
                                ContentExtended.class);
                        intent.putExtra("title", d[2].get(position).getTitle());
                        intent.putExtra("content", d[2].get(position).getContent());
                        startActivity(intent);
                    }
                });
                break;

        }

Answer 1

在我看来，除了d数组的索引之外，整个代码都被复制了。所以，它会是这样的：

public void method(int pageNumber) {
     final ListView list = (ListView)rootView.findViewById(R.id.list);
     BinderData bindingData = new BinderData(this.getActivity(), d[pageNumber]);
     list.setAdapter(bindingData);
     list.setOnItemClickListener(new OnItemClickListener() {
         @Override
         public void onItemClick(AdapterView<?> a, View v, int position, long id) {
             if (d[pageNumber].get(position).getItemType() == 0
                            || d[pageNumber].get(position).getItemType() == 3
                            || d[pageNumber].get(position).getItemType() == 2)
                 return;
             Intent intent = new Intent(Schedule.this.getActivity(),
                            ContentExtended.class);
             intent.putExtra("title", d[pageNumber].get(position).getTitle());
             intent.putExtra("content", d[pageNumber].get(position).getContent());
             startActivity(intent);
         }
     });
}

Answer 2

on onClick check on pageNumber我看到了，在每种情况下，我看到的唯一区别是数组d的索引。在onClick方法中尝试这个：

       final ListView list1 = (ListView)rootView.findViewById(R.id.list);
        BinderData bindingData = new BinderData(this.getActivity(), d[pageNumber]);
        list1.setAdapter(bindingData);
        list1.setOnItemClickListener(new OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> a, View v, int position, long id) {
                if (d[0].get(position).getItemType() == 0
                        || d[pageNumber].get(position).getItemType() == 3
                        || d[pageNumber].get(position).getItemType() == 2)
                    return;
                Intent intent = new Intent(Schedule.this.getActivity(),
                        ContentExtended.class);
                intent.putExtra("title", d[pageNumber].get(position).getTitle());
                intent.putExtra("content", d[pageNumber].get(position).getContent());
                startActivity(intent);
            }
        });

Answer 3

您无法使用loops进行切换。你可以使用if。因为我看到你的代码只在数组d索引中的每种情况下只有区别。所以你不想切换或者也不想。

public void onClick(int pageNumber) { 
 //your implementaion
}

现在您可以将页码传递给此方法

动态实现switch语句

3 个答案: