为什么printf在我的程序中不起作用(尝试刷新)

时间:2013-06-27 02:54:13

标签: c printf fflush

我在C之前学过Objective-C,现在我回到C,我不明白为什么循环中的printf()不起作用?有人可以告诉我吗?

如果有人想知道,该计划是Skiena和Revilla的“编程挑战”一书中的第一个挑战。

#include <stdio.h>
#include <stdbool.h>

static int inputInt;
static int secondInt;
int returnCycleNumber(int givenNumber);

int returnCycleNumber(int givenNumber) {
    bool initial = true;
    int counter = 1;

    do
    {
        if (givenNumber % 2 != 0)
        {
            givenNumber = givenNumber * 3 + 1;
            counter = counter + 1;

            printf("\n%i", givenNumber);
        }
        else
        {
            givenNumber = givenNumber / 2;
            counter = counter + 1;

            printf("\n%i", givenNumber);
        }

        if (givenNumber == 1) {
            initial = false;
        }

    } while (initial == true && givenNumber > 1);

    return counter;
}

int main(int argc, const char * argv[])
{
    scanf("%i %i", &inputInt, &secondInt);
    fflush(stdout);

    int arrayCount[secondInt];

    for (int counter = 0; counter == (secondInt - inputInt); counter++ ) {
        arrayCount[counter] = returnCycleNumber(inputInt + counter);
    }

    printf("\n%i", arrayCount[1]);


    return 0;
}

2 个答案:

答案 0 :(得分:3)

counter == (secondInt - inputInt)

你想要!=或&lt;

答案 1 :(得分:0)

试试这个

for (int counter = 0; counter < (secondInt - inputInt); counter++ ) {