Question

我现在已经搞乱了几个小时了。它必须是愚蠢的东西，但我只是没有看到它。为什么我的db-＆gt; get（）没有返回任何行？这是我第一次尝试MVC框架。我在Ubuntu中安装了apache2，mysql，php5和codeigniter。出于某种原因，我似乎无法让模型访问数据库中的数据。

# cat config/database.php 
<?php  if ( ! defined('BASEPATH')) exit('No direct script access allowed');

$active_group = 'default';
$active_record = TRUE;

$db['default']['hostname'] = '127.0.0.1';
$db['default']['username'] = 'webuser';
$db['default']['password'] = 'webuser';
$db['default']['database'] = 'product';
$db['default']['dbdriver'] = 'mysql';
$db['default']['dbprefix'] = '';
$db['default']['pconnect'] = TRUE;
$db['default']['db_debug'] = FALSE;
$db['default']['cache_on'] = FALSE;
$db['default']['cachedir'] = '';
$db['default']['char_set'] = 'utf8';
$db['default']['dbcollat'] = 'utf8_general_ci';
$db['default']['swap_pre'] = '';
$db['default']['autoinit'] = TRUE;
$db['default']['stricton'] = FALSE;

# cat models/productmodel.php 
<?php
    class Productmodel extends CI_Model {

            public function __construct() {
                    parent::__construct();
                    $this->load->database();
            }

            public function ListData() {

                    $query = $this->db->get("Fruit");

                    if ($query->num_rows() > 0) {
                            foreach ( $query->result() as $row ) {
                                    echo "VALUE: <BR>\n";
                            }
                    } else {
                            $string = $this->db->last_query();
                            echo "$string <BR>\n";
                    }

                    return $query->result();
            }
    }
?>

# cat controllers/productcontroller.php 
<?php
    class Productcontroller extends CI_Controller {
            public function index() {
                    $this->load->model('productmodel');

                    $data['query'] = $this->productmodel->ListData();

                    $data['title'] = 'MVC Test';
                    $data['heading'] = 'Data From product.Fruit';
                    $this->load->view('content', $data);
            }
    }
?>

# cat views/content.php 
<html>
  <head>
    <title><?php echo $title;?></title>
  </head>
  <body>
    <h1><?php echo $heading;?></h1>
    <?php foreach ($query AS $value) {echo "Value: $value <BR>\n"; } ?>
  </body>
</html>

# echo "SELECT * FROM product.Fruit" | mysql -h 127.0.0.1 -u webuser --password=webuser
name      color   size
Apple      Red     1
Orange     Orange  1
Watermelon Green   3
Grape      Green   0
Cherry     Red     0
HoneyDew   Green   2

Answer 1

试试这个：

<?php
    $data   = array();                                  #array declaration
    $query  = $this->db->get("Fruit");                  #actual get all query
    if($query->num_rows() > 0){                         #checking for the existence of rows
        $data   = $query->result_array();               #will fetch all the tuples in the data array 
    }
    echo "<pre>";print_r($data);echo "</pre>";die;      #print the data array and die
?>

Answer 2

如上所述Here 使用 $this->db->last_query(); 进行调试

Answer 3

尝试这个。它将为您提供表中的数据和表中包含的记录数。

public function your_method()
{      
        $this->db->select('*')->from('your_table');
        $query = $this->db->get();
        if($query->num_rows() > 0) 
        {
            $res['your_data']    = $query->result(); 
            $res['num_rows']     = $query->num_rows();

        }
        //if your_table contains data/records or not the following code will give you result in both the cases. 
        echo "<pre>";print_r($res);die; 

}

CodeIgniter没有从get（）返回的行

3 个答案: