我有一个AngularJS前端通过domain.com/index.html提供。我的API调用都位于domain.com/api/*的相同域范围内。我想启用标准用户名/密码身份验证。但是，我需要Silex后端做的就是设置会话并在登录时返回200个成功或401失败状态代码。我发现了来自silex，symfony2文档的代码片段为SO，但却无法让它完全正确。我基本上设置了我的自定义成功/失败自定义处理程序来返回代码并将它们应用到防火墙。我在防火墙/表单设置中的“check_path”似乎是唯一真正重要的和平。
这是大部分代码。希望它的格式足以让你提供帮助。谢谢！
app.php
// Setup sessions
$app->register(new Silex\Provider\SessionServiceProvider());
// General Service Provder for Controllers
$app->register(new Silex\Provider\ServiceControllerServiceProvider());
$app['security.authentication.success_handler.auth'] = $app->share(function ($app) {
return new ChrDb\Security\AuthSuccessHandler();
});
$app['security.authentication.failure_handler.auth'] = $app->share(function ($app) {
return new ChrDb\Security\AuthFailureHandler();
});
// Define a custom encoder for Security/Authentication
$app['security.encoder.digest'] = $app->share(function ($app) {
// uses the password-compat encryption
return new BCryptPasswordEncoder(10);
});
// Security definition.
$app->register(new SecurityServiceProvider(), array(
'security.firewalls' => array(
// Login URL is open to everybody.
// 'login' => array(
// 'pattern' => '^/api/login$',
// 'anonymous' => true,
// ),
// Any other URL requires auth.
'auth' => array(
//'pattern' => '^.*$',
'pattern' => '^/api$',
'form' => array(
'login_path' => '/api/auth/login',
'check_path' => '/api/login',
'username_parameter' => 'username',
'password_parameter' => 'password'
),
'logout' => array('logout_path' => '/api/auth/logout'),
'users' => $app->share(function() use ($app) {
return new ChrDb\Security\UserProvider($app);
}),
),
),
));
$app['api.auth.controller'] = $app->share(function() use ($app) {
return new ChrDb\Api\AuthController();
});
$app->get('/api/auth/login', "api.auth.controller:loginAction");
$app->get('/api/auth/logout', "api.auth.controller:logoutAction");
以下是相关代码的其余部分：
<?php
namespace ChrDb\Security;
use Symfony\Component\Security\Core\User\UserProviderInterface;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\User;
use Symfony\Component\Security\Core\Exception\UnsupportedUserException;
use Symfony\Component\Security\Core\Exception\UsernameNotFoundException;
use Doctrine\DBAL\Connection;
class UserProvider implements UserProviderInterface
{
public function __construct($app)
{
$this->app = $app;
}
public function loadUserByUsername($username)
{
$this->app['monolog']->addDebug('WTFFFF: ' . $username);
$stmt = $this->app['db']->executeQuery("SELECT * FROM user WHERE username = ?", array(strtolower($username)));
if (!$user = $stmt->fetch()) {
throw new UsernameNotFoundException(sprintf('Username "%s" does not exist.', $username));
}
return new User($user['username'], $user['pwd_hash'], explode(',', $user['roles']), true, true, true, true);
}
public function refreshUser(UserInterface $user)
{
if (!$user instanceof User) {
throw new UnsupportedUserException(sprintf('Instances of "%s" are not supported.', get_class($user)));
}
return $this->loadUserByUsername($user->getUsername());
}
public function supportsClass($class)
{
return $class === 'Symfony\Component\Security\Core\User\User';
}
}
<?php
namespace ChrDb\Security;
use Symfony\Component\Security\Http\Authentication\AuthenticationSuccessHandlerInterface;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;
class AuthSuccessHandler implements AuthenticationSuccessHandlerInterface
{
/**
* This is called when an interactive authentication attempt succeeds. This
* is called by authentication listeners inheriting from
* AbstractAuthenticationListener.
*
* @param Request $request
* @param TokenInterface $token
*
* @return Response never null
*/
public function onAuthenticationSuccess(Request $request, TokenInterface $token)
{
return new Response('Login was successful.', 200);
}
}
<?php
namespace ChrDb\Security;
use Symfony\Component\Security\Core\Exception\AuthenticationException;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\Security\Http\Authentication\AuthenticationFailureHandlerInterface;
class AuthFailureHandler implements AuthenticationFailureHandlerInterface
{
/**
* This is called when an interactive authentication attempt fails. This is
* called by authentication listeners inheriting from
* AbstractAuthenticationListener.
*
* @param Request $request
* @param AuthenticationException $exception
*
* @return Response The response to return, never null
*/
public function onAuthenticationFailure(Request $request, AuthenticationException $exception)
{
return new Response('Login failed.', 500);
}
}
以下是我在尝试调用/ api / login url时遇到的错误：curl -d'username=z@z.com& password = test'http://domain.com/api/login，以获得200或401响应
[2013-06-26 13:10:48] myapp.INFO: > POST /api/login [] []
[2013-06-26 13:10:48] myapp.CRITICAL: LogicException: The controller must return a response (null given). Did you forget to add a return statement somewhere in your controller? (uncaught exception) at /Users/guachiman/Sites/chrdb/vendor/symfony/http-kernel/Symfony/Component/HttpKernel/HttpKernel.php line 135 {"exception":"[object] (LogicException: The controller must return a response (null given). Did you forget to add a return statement somewhere in your controller? at /Users/guachiman/Sites/chrdb/vendor/symfony/http-kernel/Symfony/Component/HttpKernel/HttpKernel.php:135)"} []
是否有任何明显的遗漏会导致此错误？我不知道它指的是哪个控制器返回null。我觉得我可能需要设置我自己的自定义ServiceProvider，但我希望只是设置成功/失败处理程序就足够了。我很确定我只是遇到了login_path / check路径的问题。