我一直试图将Perl Monks(http://www.perlmonks.org/?node_id=735923)的第一个答案扩展到线程模型,但无济于事。我一直遇到无法传递coderef的问题
在我的超类中,我将线程池定义为包变量,因此它可以在子类之间共享:
package Things::Generic;
my $Qwork = new Thread::Queue;
my $Qresults = new Thread::Queue;
my @pool = map { threads->create(\&worker, $Qwork, $Qresults) } 1..$MAX_THREADS;
sub worker {
my $tid = threads->tid;
my( $Qwork, $Qresults ) = @_;
while( my $work = $Qwork->dequeue ) {
my $result = $work->process_thing();
$Qresults->enqueue( $result );
}
$Qresults->enqueue( undef ); ## Signal this thread is finished
}
sub enqueue {
my $self = shift;
$Qwork->enqueue($self);
}
sub new {
#Blessing and stuff
}
.
.
现在为子类。保证他们有一个process_thing()方法。
package Things::SpecificN;
use base qw (Things::Generic);
sub new() {
#instantiate
}
sub do_things {
my $self = shift;
#enqueue self into the shared worker pool so that "process_thing" is called
$self->enqueue();
}
sub process_thing() {
#Do some work here
return RESULT;
}
#
Main
my @things;
push @things, Things::Specific1->new();
push @things, Things::Specific2->new();
.
.
push @things, Things::SpecificN->new();
#Asynchronously kick off "work"
foreach my $thing (@things) {
$thing->do_things();
}
我的目标是列出" work"在队列上。每个线程都会从队列中拉出工作并执行它,无论它是什么。每件事都有自己独特的工作,但是保证工作的功能被称为" process_thing"。我只是希望线程池从队列中获取一个条目并执行"某些事情"。我想我正在描述类似于Android AsyncTask的功能。
My Perl对于Thread :: Queue :: Any
来说不够高答案 0 :(得分:1)
$Qwork->enqueue($self);
代替$self->enqueue();