我需要构建的查询是:
query = query.Where(s =>
(
(s.Title.Contains(title1) && s.EpisodeTitle.Contains(episodeTitle1))
||
(s.Title.Contains(title2) && s.EpisodeTitle.Contains(episodeTitle2)))
);
唯一的问题是,s.Title和s.EpisodeTitle是动态的。
意味着以下变量可以成为查询的一部分:
(string title1 = null,
string title2 = null,
string episodeTitle1 = null,
string episodeTitle2 = null,
string genre = null,
string directorName = null,
string releaseYear = null,
string seasonEpisode = null,
string showTypeDescription = null)
e.g。
query = query.Where(s =>
(
(s.DirectorName.Contains(directorName) && s.ShowTypeDescription.Contains(ShowTypeDescription))
||
(s.releaseYear.Contains(releaseYear) && s.genre.Contains(genre)))
);
在任何类型的组合中。
如何在不考虑每个单一可能性的情况下构建此查询?
答案 0 :(得分:3)
如果您只需要AND
逻辑,则可以针对需要搜索的每个属性重复调用.Where()
。
if(title != null) query = query.Where(x=>x.Title == title);
if(genre != null) query = query.Where(x=>x.Genre == genre);
如果您的查询始终具有某种结构,并且您希望忽略空搜索值,则可以执行一个大查询,但使用null检查将属性比较短路。
query = query.Where(s =>
(
((title1 == null || s.Title.Contains(title1))
&& (episodeTitle1 == null || s.EpisodeTitle.Contains(episodeTitle1))
||
((title2 == null || s.Title.Contains(title2))
&& (episodeTitle2 == null || s.EpisodeTitle.Contains(episodeTitle2))))
);
但是,如果您需要完全控制查询,那么您需要查看使用PredicateBuilder或System.Linq.Expressions来构建特定查询以搜索必要的属性。这是一个关于Linq.Expressions的有用教程 - http://msdn.microsoft.com/en-us/library/vstudio/bb882637.aspx
答案 1 :(得分:0)
最佳解决方案是将linqExtension与LINQKIT一起使用。
using (var context = new workEntities() )
{
Dictionary<string, List<string>> dictionary = new Dictionary<string, List<string>>();
dictionary["Title"] = new List<string> {
"Network Engineer",
"Security Specialist",
"=Web Developer"
};
dictionary["Salary"] = new List<string> { ">=2000" };
dictionary["VacationHours"] = new List<string> { ">21" };
dictionary["SickLeaveHours"] = new List<string> { "<5" };
dictionary["HireDate"] = new List<string> {
">=01/01/2000",
"28/02/2014"
};
dictionary["ModifiedDate"] = new List<string> { DateTime.Now.ToString() };
var data = context.Employee.CollectionToQuery(dictionary).ToList();
}