Question

我希望得到最近提交的10个补丁（前10个补丁ID）从以下查询开始，我在10上收到错误消息。错误是syntax error, unexpected NUM, expecting END_OF_INPUT, or ';'。可能会在以下查询中导致此错误吗？

SELECT TOP 10 synth.*
FROM (
    SELECT p.`id`, 
        p.`patchName`,
        p.`description`,
        p.`tfsID`,
        p.`codeRelease`,
        s.`name`, 
        d.`deployStatus`, 
        d.`deployedDate`,
        t.`testedStatus`,
        t.`testedDate`
    FROM `patches` AS p 
    JOIN `deployed` AS d ON p.`id` = d.`PatchID`
    JOIN `servers` AS s ON d.`serverID` = s.`id`
    JOIN `tested` AS t ON p.`id` = t.`patchID`
) synth
ORDER BY synth.id DESC

Answer 1

TOP 10是MS SQL特有的东西，在MySQL中他们使用LIMIT代替。

SELECT p.`id`, 
    p.`patchName`,
    p.`description`,
    p.`tfsID`,
    p.`codeRelease`,
    s.`name`, 
    d.`deployStatus`, 
    d.`deployedDate`,
    t.`testedStatus`,
    t.`testedDate`
FROM `patches` AS p 
JOIN `deployed` AS d ON p.`id` = d.`PatchID`
JOIN `servers` AS s ON d.`serverID` = s.`id`
JOIN `tested` AS t ON p.`id` = t.`patchID`
ORDER BY p.`id` DESC
LIMIT 10

每个服务器的限制语法相当不同，这里有一个概述：

从第100行开始，显示10个结果（即101,102,103 ......）

PostgreSQL, MySQL and DB2: SELECT * FROM table LIMIT 10 OFFSET 100
Informix: SELECT SKIP 100 FIRST 10 FROM table 
Microsoft SQL Server and Access: SELECT TOP 10 * FROM table -- skipping the offset here as it's a pain, search for it if you need it :)
Oracle: SELECT * FROM (SELECT *, ROW_NUMBER() OVER ORDER BY id) rnk FROM table) WHERE rnk BETWEEN 100 AND 110

使用mysql选择前10个最新的东西

1 个答案: