Question

我有一个文本文档，我试图找到返回并用逗号替换它们。我一直收到语法错误，最后的打印功能突出显示，但我不知道出了什么问题。

orders = []
try:
    with open('vlc.txt') as data:
        for each_line in data:
            try:
                each_line.replace("/n", ",")
                order = order.strip()
                orders.append(order)

            except ValueError:
                pass
with open("vlc_clean.txt","wb") as vlc_file:
    pickle.dump(orders, vlc_file)

except IOError as err:
    print('File Error: ' + str(err))

except pickle.PickleError as perr:
    print('Pickling error: ' + str(perr)

print(orders)

Answer 1

字符串在python中是不可变的，因此您必须将该replace操作的返回值赋给某个变量：

order = each_line.replace("\n", ",").strip()  #use '\n' not '/n'

此行缺少结束)，这就是您获得SyntaxError的原因：

except pickle.PickleError as perr:
    print('Pickling error: ' + str(perr))
                                        ^ 
                                        |
                                     missing

Answer 2

正如我在上面的评论中所写，您应该使用“\ n”作为换行符，并注意您的变量。

这是工作代码（我忽略了保存作为泡菜）：

orders = []
try:
    with open('vlc.txt') as data:
        for each_line in data:
            try:
                order = each_line.replace("\n", ",").strip()
                orders.append(order)

            except ValueError:
                pass
except:
    pass

print(orders)

剥离返回并用Python用逗号替换它们

2 个答案: