我想在几个循环中打印出一堆行,我想找到一种不使用\n
打印行的方法,因为在每个循环完成后添加一个空行。我所拥有的代码示例如下:
def compose_line6(self, pointers, pointers_synset_type):
self.line6 = ''
for A, B in zip(pointers, pointers_synset_type):
self.line6 += 'http://www.example.org/lexicon#'+A+' http://www.monnetproject.eu/lemon#pos '+B+'\n'
return self.line6
def compose_line7(self, pointers, pointer_source_target):
self.line7 = ''
for A, B in zip(pointers, pointer_source_target):
self.line7 += 'http://www.example.org/lexicon#'+A+' http://www.monnetproject.eu/lemon#source_target '+B+'\n'
return self.line7
def compose_contents(self, line1, line2, line3, line4, line5, line6, line7):
self.contents = '''\
'''+line1+'''
'''+line2+'''
'''+line3+'''
'''+line4+'''
'''+line5+'''
'''+line6+'''
'''+line7+''''''
return self.contents
def print_lines(self, contents):
print (contents)
当我打印这些时,会发生这种情况:
http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#pos n
http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#pos a
http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#source_target 0000
http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#source_target 0401
http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#source_target 0302
http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#source_target 0203
http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#source_target 0101
我想这样:
http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#pos n
http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#pos a
http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#source_target 0000
http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#source_target 0401
http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#source_target 0302
http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#source_target 0203
http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#source_target 0101
帮助非常棒,谢谢
答案 0 :(得分:2)
在添加换行符之前,您需要关闭引号:
'''\
'''+line1+'''
'''+line2+'''
'''+line3+'''
'''+line4+'''
'''+line5+'''
'''+line6+'''
'''+line7+''''''
您逃脱了第一个换行符,但它仍然在line1
后面添加了4个空格。试试这个:
print("\n".join([line1, line2, line3, line4, line5, line 6, line7]))
答案 1 :(得分:2)
使用:
def compose_contents(self, line1, line2, line3, line4, line5, line6, line7):
self.contents = '\n'.join([line1, line2, line3, line4, line5, line6, line7])
return self.contents
和
print contents,
注意最后的逗号!
答案 2 :(得分:1)
在Python 2.x中,它将是print "Text",
- 逗号之后没有任何内容。
在Python 3.x中它将是print("Text", end="")
- 只是print()
函数的特殊参数。