Question

是否可以在sql下创建生成条件：

select name from (select distinct name from person) as aliasname  order by lower(name);

这里有两个sql -

select distinct name from person
select name from <output of 1> as aliasname order by lower(name)

我想创建条件，然后执行criteria.list()

Answer 1

我认为，这将满足您的需求：

criteria.addOrder(Order.asc("name").ignoreCase())
        .setProjection(Projections.distinct(Projections.property("name")))
        .list();

或者，此标准使用名为projection的DetachedCriteria作为子查询：

DetachedCriteria distinctNamesCriteria = DetachedCriteria.forClass(Person.class);
distinctNamesCriteria.setProjection(Projections.distinct(Projections.property("name")));

criteria.add(SubQueries.propertyIn("name", distinctNamesCriteria))
        .addOrder(Order.asc("name").ignoreCase())
        .list();

Answer 2

我没有给你答案，但为什么你要做第二次选择？

SELECT DISTINCT NAME FROM PERSON AS ALIASNAME ORDER BY LOWER(NAME)

将返回相同的数据。

使用条件的Hibernate嵌套查询

2 个答案: