Codeigniter Active记录响应与PhPmyAdmin SQL查询不同

时间:2013-06-26 11:32:42

标签: codeigniter activerecord phpmyadmin

我在codeigniter有效记录表单MyPhpAdmin执行查询时得到的结果不同

使用MyPhpAdmin

运行以下查询
SELECT * FROM (`ingredients`) LEFT JOIN `product_ingredients` ON `ingredients`.`ingredient_id` = `product_ingredients`.`ingredient_id` AND `product_id` = 46

给出所需的结果,其中包括返回的两个成分记录的ingredient_id。

Array ( [0] => stdClass Object ( [ingredient_id] => 1 [display] => Sweet Almond Oil [slug] => sweet-almond-oil [title] => Sweet Almond Oil [description] => Sweet Almond Oil [featured_image_url] => [product_ingredient_id] => 10 [product_id] => 46 [display_position] => 2 [key_ingredient] => 0 ) [1] => stdClass Object ( [ingredient_id] => 2 [display] => Shea Butter [slug] => shea-butter [title] => Shea Butter [description] => Shea Butter [featured_image_url] => [product_ingredient_id] => [product_id] => [display_position] => [key_ingredient] => ) )

但是,如果我使用Codeigniter Active记录执行此查询,并使用以下代码:

$this->db->select('*');
$this->db->join('product_ingredients', 'ingredients.ingredient_id = product_ingredients.ingredient_id AND `product_id` = 46', 'left');
$query = $this->db->get('ingredients'); 

然后结果数组缺少第二个成分结果的ingredient_id,即:

Array ( [0] => stdClass Object ( [ingredient_id] => 1 [display] => Sweet Almond Oil [slug] => sweet-almond-oil [title] => Sweet Almond Oil [description] => Sweet Almond Oil [featured_image_url] => [product_ingredient_id] => 10 [product_id] => 46 [display_position] => 2 [key_ingredient] => 0 ) [1] => stdClass Object ( [ingredient_id] => [display] => Shea Butter [slug] => shea-butter [title] => Shea Butter [description] => Shea Butter [featured_image_url] => [product_ingredient_id] => [product_id] => [display_position] => [key_ingredient] => ) )

任何帮助都会非常感激......

1 个答案:

答案 0 :(得分:0)

检查出来

$this->db->select('i.*');
$this->db->from('ingredients i');
$this->db->join('product_ingredients pi', 'i.ingredient_id = pi.ingredient_id', 'left');
$this->db->where('pi.product_id',46);
$query = $this->db->get()->result_array();