Question

我有一个像这样的字符串：

288.999,224.004 283.665,258.338 313.332,293.005 312.332,336.671 270.999,389.338 371.998,412.338

我尝试将数据解析为浮点值，但我想对其进行排序！逗号之前的值应该是我的x值，逗号之后的值应该是y值。

Pattern p = Pattern.compile("[0-9]+.[0-9]*");
Matcher m = p.matcher(pointString);
while(m.find())
{
   System.out.print("x:"+m.group(0)); //x- Values
  // System.out.print("y:"+m.group(1)); //y- Values
}

此代码只创建一个组...我应该如何更改我的String模式以获得具有y值的第二个组...

青睐的结果：

x:288.999
y:224.004 
x:283.665
y:258.338 
....

Answer 1

保持简单，split就够了：

String input = "288.999,224.004 283.665,258.338 313.332,293.005 312.332,336.671 270.999,389.338 371.998,412.338";

String[] points = input.split(" ");
for (String point : points) {
  String[] coordinates = point.split(",");
  System.out.println("x:" + coordinates[0]);
  System.out.println("y:" + coordinates[1]);
}

Answer 2

您正在寻找的模式：

((?:\\d*\\.\\d+)|(?:\\d+\\.\\d*)) *, *((?:\\d*\\.\\d+)|(?:\\d+\\.\\d*))

另外，组（0）会带来整场比赛，你宁愿寻找组（1）和组（2）

Answer 3

这将有效

 String str = "288.999,224.004 283.665,258.338 313.332,293.005 312.332,336.671 270.999,389.338 371.998,412.338";
    String[] points=str.split(" ");
    String[] point=new String[2];
    for(int i=0;i<points.length;i++){
        point=points[i].split(",");
        System.out.println("X-val: "+point[0]);
        System.out.println("Y-val: "+point[1]);
    }

正则表达式：从String中提取浮点数据并对其进行分组

3 个答案: