我有这样的查询...
+-----+------------+--------+---------+---------+
| seq | fld_Date | CBU_IN | CBU_OUT | Balance |
+-----+------------+--------+---------+---------+
| 41 | 2012-10-08 | 150.00 | 0.00 | 150.00 |
| 42 | 2012-10-15 | 50.00 | 0.00 | 200.00 |
| 43 | 2012-10-22 | 50.00 | 0.00 | 250.00 |
| 44 | 2012-10-29 | 50.00 | 0.00 | 300.00 |
| 45 | 2012-11-05 | 50.00 | 0.00 | 350.00 |
| 46 | 2012-11-12 | 50.00 | 0.00 | 400.00 |
| 47 | 2012-11-19 | 50.00 | 0.00 | 450.00 |
+-----+------------+--------+---------+---------+
所有我想要的是这种输出,其中下一行日期来自fld_Date的下一行。
+-----+------------+---------------+--------+---------+---------+
| seq | fld_Date | next_row_date | CBU_IN | CBU_OUT | Balance |
+-----+------------+---------------+--------+---------+---------+
| 41 | 2012-10-08 | 2012-10-15 | 150.00 | 0.00 | 150.00 |
| 42 | 2012-10-15 | 2012-10-22 | 50.00 | 0.00 | 200.00 |
| 43 | 2012-10-22 | 2012-10-25 | 50.00 | 0.00 | 250.00 |
| 44 | 2012-10-25 | 2012-11-05 | 50.00 | 0.00 | 300.00 |
| 45 | 2012-11-05 | 2012-11-12 | 50.00 | 0.00 | 350.00 |
| 46 | 2012-11-12 | 2012-11-16 | 50.00 | 0.00 | 400.00 |
| 47 | 2012-11-16 | 2012-11-26 | 50.00 | 0.00 | 450.00 |
+-----+------------+---------------+--------+---------+---------+
你能帮我解决这个......谢谢...
这是我的查询...
SELECT
lms_savings.seq,
lms_savings.fld_Date,
FORMAT(lms_savings.CBU,2)AS CBU_IN,
FORMAT(lms_savings.CBU_OUT,2)AS CBU_OUT,
FORMAT(@Balance := @Balance + lms_savings.CBU - lms_savings.CBU_OUT,2) AS Balance
FROM lms_savings, (SELECT @Balance := 0) AS variableInit
答案 0 :(得分:0)
将您的查询代替“您的查询”
select a.seq, a.fld_Date,b.fld_Date as next_row_date,
a.CBU_IN,a.CBU_OUT,a.Balance
from ( your query ) a left outer join (your query) b
on a.seq = b.seq-1
答案 1 :(得分:0)
select a.seq, a.fld_Date, b.fld_Date as next_row_date , a.CBU_IN, a.CBU_OUT, a.Balance
from table_name a, table_name b
where a.seq = b.seq+1