我有一个简单的HTML5表单。但是当我做一个代码验证器(http://validator.w3.org/check)时,我得到了多个错误
label元素的for属性必须引用表单控件。这个错误是什么意思?它指向这一行
<label id="name0" for="Name" style="width: 180px;">Name</label>
这是我目前的表格
<div id="contact-add" title="Add New Contact" style="display: none;">
<div id="response-add"></div>
<form method="post" id="add-form">
<div class="label-input">
<label id="name0" for="Name" style="width: 180px;">Name</label>
<input type="text" id="fullname0" value="" name="name" placeholder="Enter full name..." />
<input type="hidden" name="add_account_id" id="add_account_id" value="<?php echo $add_account_id; ?>" />
</div>
<div class="label-input">
<label id="title0" for="title" style="width: 180px;">Title (Optional)</label>
<input type="text" value="" name="title" placeholder="Enter title here..." />
</div>
<div class="label-input">
<label id="email0" for="email" style="width: 180px;">Email (Optional)</label>
<input type="text" value="" id="email" name="email" placeholder="Enter email address..." />
</div>
<div class="label-input">
<label id="phone0" for="phone" style="width: 180px;">Direct Number (Optional)</label>
<input type="text" value="" id="phone_number" name="phone_number" placeholder="Enter direct number..." />
</div>
<div class="label-input">
<label id="extention0" for="extention" style="width: 180px;">Extention (Optional)</label>
<input type="text" value="" id="phone_ext" name="phone_ext" placeholder="Enter extention number..." />
</div>
<div class="label-input">
<label id="shift0" for="shift" style="width: 180px;">Work Shift</label>
<?php echo generateWorkShiftMenu($db, 'work_shift', 'Day'); ?>
</div>
</form>
</div>
答案 0 :(得分:1)
标签的for
属性必须是表单控件的id。即
<label id="name0" for="fullname0" style="width: 180px;">Name</label>
<input type="text" id="fullname0" value="" name="name" placeholder="Enter full name..." />