Question

如何使下面的黄瓜步骤更漂亮？

Then(/^I should see my (published|unpublished) project$/) do |published_state|

  if published_state == "published"
    project_name = published_name
  elsif published_state == "unpublished"
    project_name = unpublished_name 
  end

  page.should have_content(project_name)
end

中间的if语句对我来说是个问题但我需要它来接受RegEx匹配并决定是否调用“published_name”或“unpublished_name”。我希望能够做到这一点：

Then(/^I should see my (published|unpublished) project$/) do |published_state|    
  page.should have_content(published_state + "_name")
end

我也尝试了以下内容：

page.send should_or_not, have_content("#{pub_state}_name".constantize)
page.send should_or_not, have_content("#{pub_state}_name".to_sym)

基本上我想把一个字符串“发布”，并在其上添加“_name”，并将其称为方法。

Answer 1

您可以执行以下操作：

Then(/^I should see my (published|unpublished) project$/) do |published_state|
  page.should have_content(send(:"#{published_state}_name"))
end

但是，我只想写：

Then /^I should see my published project$/ do
  page.should have_content(published_name)
end

Then /^I should see my unpublished project$/ do
  page.should have_content(unpublished_name)
end

如何将一些文本附加到字符串并将其作为方法调用？

1 个答案: