键值对如何处理与已存在的键完全匹配?

时间:2013-06-25 15:02:49

标签: c# keyvaluepair

我有一个我正在插入字典的集合,并且已经输入了KVP中的值。假设我已经有一个“4000”的键并且值再次出现,该值会发生什么变化?它是否将键实例的值添加到该键已存在的值中?是否过度写入了值?

如果它过度写入,我如何在迭代值集合时添加值?

public class AccountBalance
{
    public decimal balance { get; set; }
    public bool balancesheetact { get; set; }

    public AccountBalance()
    {
        balance = 0;
        balancesheetact = false;
    }

}

Dictionary<string, List<AccountBalance>> balances = new Dictionary<string, List<AccountBalance>>();
var jentries = from je in gl.JEHeaders
               where je.ped_int_id >= beginperiod && je.ped_int_id <= endperiod
               orderby je.ped_int_id
               select je;

bool isBalanceSheet;

foreach (JEHeader header in jentries)
{
    foreach (JEDetail entry in header.JEDetails)
    {
        string subAccount = entry.ChartOfAccounts.acc_ext_id.Trim();
        string key = subAccount.Remove(0, 4);

        if (entry.ChartOfAccounts.acc_ty >= 15320 && entry.ChartOfAccounts.acc_ty <= 15322)
            isBalanceSheet = true;
        else
            isBalanceSheet = false;


        AccountBalance value = null;

        if (!balances.ContainsKey(key))
        {
            List<AccountBalance> account_balances = new List<AccountBalance>();
            //   for (int i = 0; i < 12; ++i)
            for (int i = 0; i < 14; ++i)
                account_balances.Add(new AccountBalance());

            balances.Add(key, account_balances);
        }

        //   value = balances[key][header.ped_int_id % beginperiod];
        value = balances[key][(header.ped_int_id % beginperiod) + 1];


        /// NEW
        if (header.ped_int_id == 637)
            value = balances[key][0];
        ///  end NEW

        if (entry.jnl_pst_deb_at != null)
            value.balance += entry.jnl_pst_deb_at.HasValue ? entry.jnl_pst_deb_at.Value : 0;
        if (entry.jnl_pst_crd_at != null)
            value.balance -= entry.jnl_pst_crd_at.HasValue ? entry.jnl_pst_crd_at.Value : 0;

        if (isBalanceSheet == true)
            value.balancesheetact = true;
        else
            value.balancesheetact = false;


    }
}

balances = balances.OrderBy(kvp => kvp.Key).ToDictionary(xyz => xyz.Key, xyz => xyz.Value);
int row = 0;
decimal ytdbalance;
foreach (KeyValuePair<string, List<AccountBalance>> account in balances)
{
    row++;
    //string subAccount = account.Key.Remove(0, 4);
    workbook.AddCell(row, 0, account.Key);
    ytdbalance = 0;

    bool BS = account.Value[0].balancesheetact;

    for (int i = 1; i < 13; ++i)
    {
        ytdbalance = ytdbalance + account.Value[i].balance;
        if (BS == true)
            workbook.AddCell(row, i + 1, ytdbalance);
        else
            workbook.AddCell(row, i + 1, account.Value[i].balance);

    }

}

3 个答案:

答案 0 :(得分:1)

字典是1对1地图,如果您需要1对多地图,则可以创建Lookup

Adding复制到字典会产生ArgumentException

答案 1 :(得分:1)

它会覆盖。如果您想将值添加到现有值,我相信您正在寻找:

if (dict.ContainsKey(key)) {
    dict[key] += newVal;
} else {
    dict[key] = newVal;
}

// or

int currentVal;
dict.TryGetValue(key, out currentVal);
dict[key] = currentVal + newVal;

您必须先检查它是否存在,如果存在,请添加值并重新插入字典。如果它不存在,您可以像平常一样进行设置。

在这里注意线程安全 - 如果你的字典是通过多个线程访问的,那么这段代码可能会让你的字典无法解决。

答案 2 :(得分:0)

如果您只是想随意添加值,而不是说Dictionary<String,String>,而不是只需要调用添加类似

的内容<String,List<String>>
if (!myDict.ContainsKey(someKey))
{
   myDict.Add(someKey,new List<String>());
}
myDict[somekey].Add(somevalue);

无论如何要做到这一点。