Question

我正在为向量内uint8_t指针内的向量内的boost::tuple赋值。赋值本身似乎运行良好，但数据似乎在分配后立即释放，因为它往往被其他数据覆盖。

我在想packet* a = new packet;应该分配一个新的packet，而下面的.push_back(a)应该复制指针并引用相同的值 - 显然我错了。我希望有人看到我的错误;会感激任何帮助。

typedef boost::tuple<uint8_t, uint16_t, std::vector<uint8_t> > packet;

static void assignValueToMember(uint8_t& member){
    member = 1;
}
static void assignValueToMember(uint16_t& member){
    member = 2;
}

static void assignValueToMember(std::vector<uint8_t> member){
    int maxIndex = 10;
    for (int i = 0; i < maxIndex; i++){
        uint8_t a;
        assignValueToMember(a);
        member.push_back(a);
    }
}

static void assignValueToMember(std::vector<packet*>& member){

    int maxIndex = 20;

    for (int i = 0; i < maxIndex; i++){
        packet* a = new packet;
        assignValueToMember(boost::get<0>(*a));
        assignValueToMember(boost::get<1>(*a));
        assignValueToMember(boost::get<2>(*a));

        member.push_back(a);
    }
}

void Base::test(){
    std::vector<packet*> a;
    assignValueToMember(a);

    packet* b = a.front();
    std::vector<unsigned char> c = boost::get<2>(*b);

    std::cout << c.front(); 
}

Answer 1

static void assignValueToMember(std::vector<uint8_t> member)您传递的是此向量的副本而不是引用。

std :: vector中的数据损坏 - 可能是错误的赋值

1 个答案: