Question

嗨说我有对象：

public class InvoiceLine
{
}

和

public class InvoiceHeader
{
    public char Group { get; set; }
    public List<InvoiceLine> InvoiceLines { get; set; }
}

为他们设置数据如下：

var invoiceLine1 = new InvoiceLine();
var invoiceLine2 = new InvoiceLine();
var invoiceLine3 = new InvoiceLine();
var invoiceLine4 = new InvoiceLine();
var invoiceLine5 = new InvoiceLine();
var invoiceLine6 = new InvoiceLine();
var invoiceLine7 = new InvoiceLine();
var invoiceLine8 = new InvoiceLine();

var invoiceHeader1 = new InvoiceHeader { Group = 'A', InvoiceLines = new List<InvoiceLine> { invoiceLine1, invoiceLine2 } };
var invoiceHeader2 = new InvoiceHeader { Group = 'A', InvoiceLines = new List<InvoiceLine> { invoiceLine3, invoiceLine4 } };
var invoiceHeader3 = new InvoiceHeader { Group = 'B', InvoiceLines = new List<InvoiceLine> { invoiceLine5, invoiceLine6 } };
var invoiceHeader4 = new InvoiceHeader { Group = 'B', InvoiceLines = new List<InvoiceLine> { invoiceLine7, invoiceLine8 } };

var invoiceHeaders = new List<InvoiceHeader>
{
    invoiceHeader1,
    invoiceHeader2,
    invoiceHeader3,
    invoiceHeader4
};

我想得到的是每个组的invoiceLines列表。

所以我想要A组：

invoice1，invoice2，invoice3和invoice4

和B组：

invoice5，invoice6，invoice7和invoice8

我得到的最远的是：

var invoiceLinesGroupA = invoiceHeaders.SelectMany(x => x.InvoiceLines);

据我所知，将获得所有八个invoiceLines。不知怎的，我需要按组来描述为groupA获取的组合，并为groupB做同样的事情。

任何人都可以帮忙吗？

Answer 1

您可能只想按小组对发票标题进行分组：

var groups = invoiceHeader.GroupBy(ih => ih.Group);

然后您可以访问组的行：

foreach(var group in groups)
{
    Console.WriteLine("Group " + group.Group);
    Console.WriteLine("Lines:");
    Console.WriteLine(string.Join(", ", group.SelectMany(h => h.InvoiceHeader.InvoiceLines)));
}

输出类似于

Group A
Lines:
invoice1, invoice2, invoice3, invoice4

Group B
Lines:
invoice5, invoice6, invoice7, invoice8

Answer 2

var regrouped = invoiceHeaders
    .SelectMany(
        header => header.InvoiceLines,
        (header, line) => new { header, line }
    )
    .GroupBy(
        o => o.header.Group,
        o => o.line,
        (groupName, lines) => new InvoiceHeader
        {
            Group = groupName,
            InvoiceLines = lines.ToList()
        }
    )
    .ToList();

Answer 3

请注意Enumerable.SelectMany

的重载

var result = invoiceHeaders
               .SelectMany(x => x.InvoiceLines,
                           (group, InvoiceLine)=>{group, InvoiceLine})
               .Where(res => res.group='A');

Answer 4

这应该这样做：

        var test = from h in invoiceHeaders
                   from i in h.InvoiceLines
                   group i by h.Group
                   into g
                   select new {key = g.Key, rows = g.ToArray()};

然后，您可以访问此test.Where(x => x.key == 'A').rows

之类的项目

Answer 5

var q = from current in myInvoiceHeaders
                join c in myInvoiceLines on current.Id equals c.Header.Id into linesByHeader                    
                select new {
                    Header = current,
                    Lines = linesByHeader
                };

应该在您有加入两个实体的标准的前提下工作。

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