从文件列表中读取文件

时间:2013-06-25 07:54:29

标签: python list xlrd

现在谷歌搜索这个问题已经有一段时间了,但似乎无法找到解决方案。我使用excelfiles-function创建所有excelfiles的列表,包括在指定目录中的名称中的“tst”。之后我想用locate_vals-function读取每个文档中的某些单元格,但我似乎无法从文件列表中重新扫描文件。也许有一个非常简单的解决方案,我只是看不到?我得到的错误消息是在底部。

这是昨天我要求帮助的更大任务的一部分(Search through directories for specific Excel files and compare data from these files with inputvalues),但我似乎无法找到这个问题的任何答案我认为它可能最好给它一个自己的线程。如果我错了,请纠正我,我会将其删除:)

import xlrd
import os, fnmatch

#globals

start_dir = 'C:/eclipse/TST-folder'

def excelfiles(pattern):
    file_list = []
    for root, dirs, files in os.walk(start_dir):
        for filename in files:
            if fnmatch.fnmatch(filename.lower(), pattern):
                if filename.endswith(".xls") or filename.endswith(".xlsx") or filename.endswith(".xlsm"):
                    file_list.append(os.path.join(root, filename))
    return file_list

file_list = excelfiles('*tst*')     # only accept docs hwom title includes tst
for i in file_list: print i


'''Location of each val from the excel spreadsheet'''


 def locate_vals():
     val_list = []
     for file in file_list:
         wb = xlrd.open_workbook(os.path.join(start_dir, file))
         sheet = wb.sheet_by_index(0)
         for vals in file:
             weightvalue = file_list.sheet.cell(3, 3).value
             lenghtvalue = sheet.cell(3, 2).value
             speedval = sheet.cell(3, 4).value

ERRORMESSAGE:

Traceback (most recent call last):
  File "C:\Users\Håvard\Documents\Skulearbeid\UMB\4. Semester Vår\Inf120 Programmering og databehandling\Workspace\STT\tst_mainsheet.py", line 52, in <module>
    print locate_vals()
  File "C:\Users\Håvard\Documents\Skulearbeid\UMB\4. Semester Vår\Inf120 Programmering og databehandling\Workspace\STT\tst_mainsheet.py", line 48, in locate_vals
    weightvalue = file_list.sheet.cell(3, 3).value
AttributeError: 'list' object has no attribute 'sheet'

3 个答案:

答案 0 :(得分:2)

错误表示您需要的一切:

  

AttributeError:'list'对象没有属性'sheet'

file_list是文件名列表,list在python中没有sheet属性。

所以,你只需要替换:

weightvalue = file_list.sheet.cell(3, 3).value

weightvalue = sheet.cell(3, 3).value

答案 1 :(得分:2)

您的追溯显示的问题确实是这样:

weightvalue = file_list.sheet.cell(3, 3).value

应该是这样的:

weightvalue = sheet.cell(3, 3).value

但是,您的代码中存在更多问题。我做了一些小修改,并在评论中标记了它们:

import xlrd
import os, fnmatch

start_dir = 'C:/eclipse/TST-folder'

def excelfiles(pattern):
    file_list = []
    for root, dirs, files in os.walk(start_dir):
        for filename in files:
            if fnmatch.fnmatch(filename.lower(), pattern):
                if filename.endswith(".xls") or filename.endswith(".xlsx") or filename.endswith(".xlsm"):
                    file_list.append(os.path.join(root, filename))
    return file_list

file_list = excelfiles('*tst*')     # only accept docs hwom title includes tst
for i in file_list: print i


'''Location of each val from the excel spreadsheet'''


def locate_vals():
    val_dict = {}
    for filename in file_list:
        wb = xlrd.open_workbook(os.path.join(start_dir, filename))
        sheet = wb.sheet_by_index(0)

        # problem 2: extract these values once per sheet
        weightvalue = sheet.cell(3, 3).value
        lengthvalue = sheet.cell(3, 2).value
        speedvalue = sheet.cell(3, 4).value

        # problem 3: store them in a dictionary, keyed on filename
        val_dict[filename] = [weightvalue, lengthvalue, speedvalue]

    # dictionary keyed on filename, with value a list of the extracted vals
    return val_dict

print locate_vals()

答案 2 :(得分:1)

变化:

weightvalue = file_list.sheet.cell(3, 3).value

为:

weightvalue = sheet.cell(3, 3).value