Question

我想在android vlc应用程序中订阅MediaPlayer缓冲事件。

我编辑了EventHandler类并取消注释了事件常量。

public static final int MediaPlayerBuffering            = 0x103; // ** uncommented this**
public static final int MediaPlayerPlaying                = 0x104;

然后我在libvlcjni.c中添加了变量

libvlc_event_manager_t *ev = libvlc_media_player_event_manager(mp);
static const libvlc_event_type_t mp_events[] = {
    libvlc_MediaPlayerPlaying,
    libvlc_MediaPlayerPaused,
    libvlc_MediaPlayerEndReached,
    libvlc_MediaPlayerStopped,
    libvlc_MediaPlayerVout,
    libvlc_MediaPlayerPositionChanged,
    libvlc_MediaPlayerEncounteredError,
    libvlc_MediaPlayerBuffering // **added this here**
};

重新编译jni以获取so文件，然后构建vlc应用程序，但事件似乎永远不会发生。

由于缺少带宽，当我遇到缓冲事件时，还需要链接以获取事件。

我可以在logcat中看到它在6ms内打印1001 ms缓冲区。但这来自较低层而不是java层

Answer 1

必须在libvlcjni.c文件中添加它

else if(ev->type == libvlc_MediaPlayeBuffering) {
    /* For determining the vout/ES track change */
    jstring sData = (*env)->NewStringUTF(env, "data");
    (*env)->CallVoidMethod(env, bundle, putFloat, sData, ev->u.media_player_buffer.new_cache);
    (*env)->DeleteLocalRef(env, sData);
}

希望这有助于某人

Answer 2

else if(ev->type == libvlc_MediaPlayerBuffering) { /* For determining the vout/ES track change */ jstring sData = (*env)->NewStringUTF(env, "data"); (*env)->CallVoidMethod(env, bundle, putFloat, sData, ev->u.media_player_buffering.new_cache); (*env)->DeleteLocalRef(env, sData); }

答案是ev-＆gt; u.media_player_buffering.new_cache

在VLC文件mediaPlayer.c中我找到了这段代码：

`else if( newval.i_int == INPUT_EVENT_CACHE )
   {
    event.type = libvlc_MediaPlayerBuffering;
    event.u.media_player_buffering.new_cache = (int)(100 * var_GetFloat( p_input, "cache" ));
    libvlc_event_send( p_mi->p_event_manager, &event );
}

`

和libvlc_events.h

/* media instance */ struct { float new_cache; } media_player_buffering;

然后，我编译了它并且它起作用了。特别感谢我的男孩Tracy在海岸！

启用在android-vlc中触发的MediaPlayerBuffering事件

2 个答案: